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Fittoniya [83]
3 years ago
11

499 mg sample of CuSO4. xH2O is heated and reweighed to give a mass of 319 mg. Given that the sample contains 2 mmol of Cu; what

is the value of x in CuSO4. xH2O.
Chemistry
1 answer:
nevsk [136]3 years ago
8 0

The value of x in CuSO4. xH2O is 5.

Given that;

Number of moles of anhydrous salt = Number of moles of hydrated salt

Number of moles of anhydrous salt = 319 × 10^-3

Mass of hydrated salt = 499 ×10^-3 g

Number of moles of anhydrous salt = 319 10^-3g/160 g/mol = 0.00199 moles

Number of moles of hydrated salt = 499 × 10^-3 g/ 160 + 18x

0.00199 =  499 × 10^-3 g/ 160 + 18x

0.00199 (160 + 18x) = 499 ×10^-3

0.318 + 0.036x = 0.499

0.036x = 0.499 - 0.318

0.036x = 0.181

x = 0.181/0.036

x = 5

Hence,  x in CuSO4. xH2O is 5.

Learn more: brainly.com/question/9743981

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