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Talja [164]
3 years ago
14

One star (star A) has a parallax of 3.4 arc seconds, while a second star (star B) has a parallax of 1.70 arc seconds. What can y

ou correctly conclude?
Choose:
a) Star B must have a larger proper motion than Star A

b) Star A must have a larger proper motion than Star B

c) Star A is closer to Earth than Star B

d) Star B is closer to Earth than Star A

e) Both stars are outside the Milky Way galaxy.
Physics
1 answer:
Alchen [17]3 years ago
4 0

Based of the distance of each star, we can conclude that Star A must have a larger proper motion than Star B.

The given parameters;

  • parallax of star A = 3.4 arc seconds
  • parallax of star B = 1.7 arc seconds

The distance of each star form a Parallax is calculated as

d = \frac{1}{p}

Where;

d is the distance to star, [parsecs]

p is parallax, [arc seconds]

The distance of star A;

d = \frac{1}{3.4} = 0.3 \ parsecs

The distance of start B;

d = \frac{1}{1.7} = 0.6 \ parsecs

On average, it is known that a nearby star will have a large proper motion.

Based on the distance of each star calculated above, star A is nearer and it will have a larger proper motion that star B.

Learn more here: brainly.com/question/13046296

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