NaCl when in solid state does not conduct electricity
while it does in aqueous solution.
Explanation:
NaCl (or what we call common salt) first needs to be either
melted or dissolved in a solution for it to conduct electricity. The reason for
this is that electrons in a solid state does not have enough freedom to move to
either the Cathode (-ve) or to the Anode (+ve). So in a liquid state the
electrons are now free enough to move.
Answer:
See explanation
Explanation:
The boiling point of a substance is affected by the nature of bonding in the molecule as well as the nature of intermolecular forces between molecules of the substance.
2-methylpropane has only pure covalent and nonpolar C-C and C-H bonds. As a result of this, the molecule is nonpolar and the only intermolecular forces present are weak dispersion forces. Therefore, 2-methylpropane has a very low boiling point.
As for 2-iodo-2-methylpropane, there is a polar C-I bond. This now implies that the intermolecular forces present are both dispersion forces and dipole interaction. As a result of the presence of stronger dipole interaction between 2-iodo-2-methylpropane molecules, the compound has a higher boiling point than 2-methylpropane.
I’m sorry but I cannot see the picture
A. PV=constant
752 torr = 0.989 atm
(0.989 atm)(4.38 L) = (1.88 atm)V
V = 2.30 L
B. T/V = constant
(294 K)/(4.38 L) = (448 K)/V
V = 6.67 L
Hoped this helped ( I believe it's right, sorry if it's not )
All ions because that’s what I searched up and it came out
