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swat32
2 years ago
15

¿Qué bacterias existen según su nutrición?

Chemistry
1 answer:
Maurinko [17]2 years ago
7 0

Answer:

autotrofas estrictas son aquellas bacterias incapaces de crecer usando materia orgánica como fuente de carbono. Mixotrofas son aquellas bacterias con metabolismo energético litotrofo (obtienen energía de compuestos inorgánicos), pero requieren sustancias orgánicas como nutrientes para su metabolismo biosintético.

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What is molarity of a solution containing 0.34 moles of FeCl3 in the 0.45 liters of water
Minchanka [31]
Hello!

Molarity is defined as the number of moles of a substance that can be found in 1 liter of solution. That is expressed mathematically as M=mol/L

For the FeCl₃ solution:

M= \frac{mol FeCl_3}{L sol}= \frac{0,34 moles FeCl_3}{0,45 L}= 0,756 M

So, the concentration of this solution is 0,756 M

Have a nice day!
7 0
3 years ago
How many electrons are shared in the Lewis structure
Diano4ka-milaya [45]
Hey there,

Answer:

4 valence electrons.

Hope this helps :D

<em>~Top☺</em>
3 0
3 years ago
(30 Points) You need to produce a buffer solution that has a pH of 5.02. You already have a solution that contains 10. mmol (mil
chubhunter [2.5K]
<span>By definition:

pH = pKa + log [acetate]/ [acetic acid]

so

5.02 = 4.74 + log [acetate] / 10 mmole

10mmole = 10/1000 = 0.01 mole

5.02 = 4.74 + log [acetate] / 0.01

5.02 - 4.74 = 0.28 = log [acetate] /0.01


10^0.28 = </span><span>1.90546</span> = [acetate] / 0.01 <span>
[acetate] = 0.019 mole 

= 19 millimoles

</span>
8 0
3 years ago
Read 2 more answers
Electromagnetic radiation with a wavelength of 525 nm appears as green light to the human eye. The energy of one photon of this
Sedbober [7]

<u>Answer:</u> The energy of one photon of the given light is 3.79\times 10^{-19}J

<u>Explanation:</u>

To calculate the energy of one photon, we use Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

\lambda = wavelength of light = 525nm=5.25\times 10^{-7}m        (Conversion factor:  1m=10^9nm  )

h = Planck's constant = 6.625\times 10^{-34}J.s

c = speed of light = 3\times 10^8m/s

Putting values in above equation, we get:

E=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{5.25\times 10^{-7}mm}\\\\E=3.79\times 10^{-19}J

Hence, the energy of one photon of the given light is 3.79\times 10^{-19}J

3 0
3 years ago
Cómo se puede comprobar el efecto universo​
ch4aika [34]

Answer:

???! huhhhjhhh no I speak English

Explanation:

?

7 0
3 years ago
Read 2 more answers
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