Answer:
0.80 Moles of Hydrochloric Acid would be required to produce 0.40 Moles of hydrogen gas due to the equation ratios
Explanation:
How many moles of hydrochloric acid are required to produce .40 moles of hydrogen gas?
Hydrochloric acid = HCl
Hydrogen gas = H2
H = 1+
Cl = 1-
HCL = H2 + Cl2
2HCl = H2 + Cl2
2:1:1
0.80 = 0.40 + 0.40
When you are doing a experiment, you are testing if your hypothesis is correct or false. If your hypothesis is false, you have to disgard it. If it is correct, you have to do many more parallels, and if they also confirm your hypothesis, your hypothesis can become a theory.
Answer: The answer is True
Explanation: I hope my answer helps :)
Answer:
Equilibrium constant Kc for the reaction will be 1.722
Explanation:
O2(g)+NO(g)→CO(g)+ NO2(g)
0.88 3.9 --- ---
0.88x 3.9-x x x
GIVEN:
0.88X-X= 0.11
⇒ X=0.77
CO2(g)+NO(g) → CO(g) + NO2(g)
0.88 3.9 --- ---
0.88-x 3.9-x x x
= 3.13 0.77 0.77
=0.11
Kc = ![\frac{[CO] *[NO2]} {[CO2]*[NO]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCO%5D%20%2A%5BNO2%5D%7D%20%7B%5BCO2%5D%2A%5BNO%5D%7D%20)
=
= 1.722
