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Sladkaya [172]
3 years ago
12

Someone plz help me :(

Chemistry
1 answer:
Nitella [24]3 years ago
3 0

Answer:B

Explanation:

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bonufazy [111]

Answer:four hydrogen atoms

Explanation:

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3 years ago
List five household items that contain the same chemicals as cigarettes.
WITCHER [35]

<em>Five household items that </em><em>contain</em><em> the same chemicals as cigarettes :</em><em>-</em>

  1. <em>Perfume</em>
  2. <em>Household</em><em> </em><em>cleaning</em><em> </em><em>products</em>
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  5. <em>Water</em><em> </em><em>bottles</em>

<em>They</em><em> </em><em>contain</em><em> </em><em>toxic</em><em> </em><em>substances</em><em>!</em>

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5 0
3 years ago
Use the periodic table and example bond table to answer the question.
lyudmila [28]

In keeping with the general trends, K-Br will have the smallest bond energy. The bond energy refers to the energy that keeps the atoms in a bond together.

<h3>What is bond energy?</h3>

Bond energy is the energy that is required to hold atoms together in a bond. This energy must also be supplied when the atoms are to be separated.

We have the bond energies of each of the bons in the question, we have to note that the the smallest value of bond energy is Na-Br hence in keeping with the general trends, K-Br will have the smallest bond energy.

Learn more about bond energies: brainly.com/question/14842720?

7 0
2 years ago
Whetes the most of the mass of our solar system today
Simora [160]
Planets, black wholes gravity
3 0
3 years ago
A sample of water vapor has a volume of 3.15 L, a pressure of 2.40 atm, and a temperature of 325 K. What is the new temperature,
lara31 [8.8K]

Answer:

The answer to your question is:   T2 = 235.44 °K

Explanation:

Data

V1 = 3.15 L                    V2 = 2.78 L

P1 = 2.40 atm               P2 = 1.97 atm

T1 = 325°K                    T2 = ?

Formula

\frac{P1V1}{T1} = \frac{P2V2}{T2}

Process

            T2 = (P2V2T1) / (P1V1)

            T2 = (1.97x 2.78x 325) / (2.40 x 3.15)

            T2 = 1779.895 / 7.56

            T2 = 235.44 °K

4 0
3 years ago
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