Is a star's emission spectrum unique?

What is the mass of an object with a density of 18 g/cm3 and a volume of 25 cm3

DiKsa [7]

Answer: 0.72 grams

Explanation: Mass can be extracted from the formula of density. D=M/V where D is density and V is volume. Therefore:

18 g/cm^3 = M(25 cm^3) --> Divide by 18g/cm^3 by 25 cm^3 to isolate mass. --> <u>0.72 =M </u> --> Now, to find out which unit you need to use for mass, just look at the density. You can see it is in g/cm^3, and cm^3 was already used for the volume. Thus, gram units are left, so that will be the unit needed, making the final answer 0.72 grams. Hope this helps :)

5 0

2 years ago

A vector is a quantity that has what two items

alexandr1967 [171]

A vector has a size and a direction. The size is called the magnitude of the vector.

5 0

3 years ago

Two charged spheres are 20 cm apart and exert an attractive force of 8 x 10-9 n on each other. What will the force of attraction

Pavel [41]

Answer:

$3.2\cdot 10^{-8} N$

Explanation:

The inital electrostatic force between the two spheres is given by:

$F=k\frac{q_1 q_2}{r^2}$

where

$F=8\cdot 10^{-9} N$ is the initial force

k is the Coulomb's constant

q1 and q2 are the charges on the two spheres

r is the distance between the two spheres

The problem tells us that the two spheres are moved from a distance of r=20 cm to a distance of r'=10 cm. So we have

$r'=\frac{r}{2}$

Therefore, the new electrostatic force will be

$F'=k\frac{q_1 q_2}{(r')^2}=k\frac{q_1 q_2}{(r/2)^2}=4k\frac{q_1 q_2}{r^2}=4F$

So the force has increased by a factor 4. By using $F=8\cdot 10^{-9} N$ , we find

$F'=4(8\cdot 10^{-9} N)=3.2\cdot 10^{-8} N$

6 0

3 years ago

Approximately _____ of those who suffer from anorexia nervosa literally starve themselves to death.

Vadim26 [7]

Appproximately 10% of those who suffer from anorexia nervosa literally starve themselves to death.

6 0

3 years ago

star a and star b have measured stellar parallax of 0.58 arc second and 0.73 arc second, respectively. which star is closer?

goldenfox [79]

Star B is closer than star A, because 1/ 0.58 = 1.72 pc, while 1/.73 = 1.36 pc.

<h3>What is stellar parallax and distance measurement using stellar parallax?</h3>

To calculate the distances to nearby stars, astronomers employ a phenomenon known as parallax. The apparent displacement of an object due to a change in the viewer's point of view is known as parallax. The distances between close stars can be calculated using this phenomenon. A nearer star will seem to move against the farther-off background stars as the Earth revolves around the Sun. By measuring a star's position once, then again six months later, astronomers can establish the apparent shift in location of that star. The apparent motion of the star is referred to as stellar parallax.

A straightforward correlation exists between the distance of a star and parallax angle:

$d=\frac{1}{p}$

The distance d and parallax angle p are both measured in parsecs and arcseconds, respectively.

Stellar parallax of star A= 0.58 arcseconds

Stellar parallax of star B= 0.73 arcseconds

So, on applying the formula,

The distance of the star A= 1.72pc

And the distance of the star B= 1.36pc

Therefore, star B is closer than star A.

To know more about stellar parallax, visit:

brainly.com/question/29352944

#SPJ4

3 0

1 year ago