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Lapatulllka [165]
3 years ago
15

A train travels 55 km south along a straight track in 34 minutes. What is the train's average velocity in kilometers per hour?​

Physics
2 answers:
AURORKA [14]3 years ago
4 0
Hopefully I’m not late and I apologize if I am, but the answer to your question would be 95.6 km/hr. You know you can look up your question as well to see if they already have a answer to that so you won’t waste your points.
g100num [7]3 years ago
3 0

Answer: v = 96.5 km/h

Explanation: Solve this problem using the following equation:

v= d/t

First convert t in minutes into hours

34 mins x 1 hour / 60 mins

= 0.57 h

Substitute the values

v = 55 km / 0.57 h

= 96.5 km/h

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A point charge with a charge q1 = 2.30 μC is held stationary at the origin. A second point charge with a charge q2 = -5.00 μC mo
Alla [95]

Answer:

W = 2.74 J

Explanation:

The work done by the charge on the origin to the moving charge is equal to the difference in the potential energy of the charges.

This is the electrostatic equivalent of the work-energy theorem.

W = \Delta U = U_2 - U_1

where the potential energy is defined as follows

U = \frac{1}{4\pi\epsilon_0}\frac{q_1q_2}{r^2}

Let's first calculate the distance 'r' for both positions.

r_1 = \sqrt{(x_1 - x_0)^2 + (y_1 - y_0)^2} = \sqrt{(0.170 - 0)^2 + (0 - 0)^2} = 0.170~m\\r_2 = \sqrt{(x_2 - x_0)^2 + (y_2 - y_0)^2} = \sqrt{(0.250 - 0)^2 + (0.250 - 0)^2} = 0.353~m

Now, we can calculate the potential energies for both positions.

U_1 = \frac{kq_1q_2}{r_1^2} = \frac{(8.99\times 10^9)(2.3\times 10^{-6})(-5\times 10^{-6})}{(0.170)^2} = -3.57~J\\U_2 = \frac{kq_1q_2}{r_2^2} = \frac{(8.99\times 10^9)(2.3\times 10^{-6})(-5\times 10^{-6})}{(0.3530)^2} = -0.829~J

Finally, the total work done on the moving particle can be calculated.

W = U_2 - U_1 = (-0.829) - (-3.57) = 2.74~J

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Marrrta [24]
Oh your from the other question you made I just saw it LOL.
But heres the answer click the 3 dots on the question you made or you can ask a Moderator or Administrator to remove your question with a reason.
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Answer:

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Step 2: Committee Action

As soon as a bill is introduced, it is referred to a committee. At this point the bill is examined carefully and its chances for passage are first determined. If the committee does not act on a bill, the bill is effectively "dead."

Step 3: Subcommittee Review

Often, bills are referred to a subcommittee for study and hearings. Hearings provide the opportunity to put on the record the views of the executive branch, experts, other public officials and supporters, and opponents of the legislation.

Step 4: Mark up

When the hearings are completed, the subcommittee may meet to "mark up" the bill; that is, make changes and amendments prior to recommending the bill to the full committee. If a subcommittee votes not to report legislation to the full committee, the bill dies. If the committee votes for the bill, it is sent to the floor.

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After receiving a subcommittee's report on a bill the full committee votes on its recommendation to the House or Senate. This procedure is called "ordering a bill reported."

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Step 7: Referral to Other Chamber

When the House or Senate passes a bill, it is referred to the other chamber, where it usually follows the same route through committee and floor action. This chamber may approve the bill as received, reject it, ignore it, or change it.

Step 8: Conference Committee Action

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After both the House and Senate have approved a bill in identical form, it is sent to the president. If the president approves of the legislation, he signs it and it becomes law. Or, if the president takes no action for ten days, while Congress is in session, it automatically becomes law.If the president opposes the bill he can veto it; or if he takes no action after the Congress has adjourned its second session, it is a "pocket veto" and the legislation dies.

Step 10: Overriding a Veto

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Explanation:

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