142 g ---------------- 6.02 x 10²³ molecules
0.920g g ------------ ( molecules )
molecules = 0.920 x ( 6.02 x 10²³ ) / 142
molecules = 5.53 x 10²³ / 142
= 3.89 x 10²¹ molecules
1 molecule P2O5 -------------------------- 7 atoms
3.89 x 10²¹ molecules -------------------- ( atoms )
atoms = ( 3.89 x 10²¹) x 7 / 1
atoms = <span>2.72 x 10²² atoms of P2O5
Hope this helps!!!
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Answer:
<h3>The answer is 122.5 g</h3>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
volume = 7 mL
density = 17.5 g/mL
We have
mass = 17.5 × 7
We have the final answer as
<h3>122.5 g</h3>
Hope this helps you
Answer:
Part A: 2N₂O(g) ⇄ 2N₂(g) + O₂(g)
Part B: -r = K*[N₂O]²
Part C: K= k1*k2
Explanation:
Part A
To do the balance chemical question for the overall chemical reaction, we must sum the reaction of the steps, eliminating the intermediaries, which are the compounds that have the same amount both at reactants and products (bolded).
N₂O(g) ⇄ N₂(g) + O(g)
N₂O(g) + O(g) ⇄ N₂(g) + O₂(g)
---------------------------------------------
2N₂O(g) + O(g) ⇄ 2N₂(g) + O(g) + O₂(g)
2N₂O(g) ⇄ 2N₂(g) + O₂(g)
Part B
The velocity of the reaction (r) can be calculated based on the reactants or based on the products. Let's do it based on the disappearing of the reactant. Because it is disappearing, the variation at its concentration must be negative, so the rate will be negative.
Let's suppose its an elementary reaction, so, the concentration of the reactant must be elevated by its coefficient. And let's call the overall rate constant as K:
-r = K*[N₂O]²
Part C
Because the steps were summed, and the reactions were not multiplied by a constant or inverted, the constant K is just the multiplication of the constants of the steps:
K= k1*k2
The mass of carbon dioxide that would be produced will be 22 kg
<h3>Combustion of carbon</h3>
The combustion of carbon in air can be represented by the equation:
C + O2 ---> CO2
The mole ratio of C to O2 to CO2 is 1:1:1.
Mole of 6kg of carbon = mass/molar mass
= 6000/12
= 500 moles
Equivalent mole of CO2 produced = 500 moles
Mass of 500 moles CO2 = mole x molar mass
= 500 x 44.01
= 22,005 g or 22 kg approximately
More on combustion reactions can be found here: brainly.com/question/13649083
