A small dense centre that has a positive charge and is surrounded by moving electrons is called an Atomic Nucleus.
Answer:
9.39 m/s
Explanation:
Using the y-direction, we can solve for the time t it takes for the cart to reach the ground.
Assume the up direction is positive and the down direction is negative.
- v₀ = 0 m/s
- a = -9.8 m/s²
- Δy = -50 m
- t = ?
Find the constant acceleration equation that contains these four variables.
Substitute known values into this equation.
Multiply and simplify.
Divide both sides of the equation by -4.9.
Square root both sides of the equation.
Now we can use this time t and solve for v₀ in the x-direction. Time is most often our link between vertical and horizontal components of projectile motion.
List out known variables in the x-direction.
- v₀ = ?
- t = 3.194382825 s
- a = 0 m/s²
- Δx = 30 m
Find the constant acceleration equation that contains these four variables.
Substitute known values into the equation.
- 30 = (v₀ · 3.194382825) + 1/2(0)(3.194382825)²
Multiply and simplify.
Divide both sides of the equation by 3.194382825.
The cart was rolling at a velocity of 9.39 m/s (initial velocity) when it left the ledge.
Answer: 4.50*10^-6T (0.00000450071T)
Explanation: A current carrying conductor has been knowing to generate a specific amount of magnetic field.
This is given by the Bio-savart law (mathematical).
The Bio-savart law is a mathematical equation that gives the value of strength of the magnetic field created by a current carrying conductor.
B=(Uo* I) /2πr
Where
B= strength of magnetic field
Uo = magnetic permeability in free space = 1.257 *10^-6
r = distance between current carrying conductor and any reference point.
By doing the neccesary algebra, we have
B=(1.257 *10^-6 * 180)/ (2 * 3.142 * 8)
B= 2.2626 *10^-4 / 50.2857
B=4.5 * 10^-6T (0.00000450071T)
Answer:
the ground when the ball hits it
Explanation:
A ball falls freely towards the Earth. If the action force is the Earth pulling down on the ball, then identify which of the following best describe the reaction force:
Answer:
d = 1.24 kg/m³
v = 0.81 m³/kg
Explanation:
To do this, we need to analyze the given data and know the expressions we need to use here to do calculations.
We have a pressure of 1.05 atm and 300 K of temperature. To determine the density, we need to use a similar expression of an ideal gas. In this case, instead of using moles, we will use density:
P = dRT
d = P/RT (1)
Where:
R: universal constant of gases
d: density.
From here we can determine the specific volume by using the following expression:
v = 1/d (2)
Now, as we are looking for density, we need to convert the units of pressure in atm to Pascal (or N/m) and the conversion is the following:
P = 1.05 atm * 1.013x10⁵ N/m atm = 106,365 N/m
Now, using R as 287 the density would be:
d = 106,365 / (287 * 300)
<h2>
d = 1.24 kg/m³</h2>
Finally the specific volume:
v = 1 / 1.41
<h2>
v = 0.81 m³/kg</h2>
Hope this helps
