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vekshin1
3 years ago
13

50 points for this please help

Physics
2 answers:
Softa [21]3 years ago
7 0

but the points are only 25

wel3 years ago
6 0

Answer:

are they talking about the form classification or..?

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A force did 80 j of work on an object in 4 m how big was the force
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Work = (force) x (distance)

80 J = (force) x (4 m)

Force = (80 J) / (4 m)  =  20 N

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If the force was kind of slanted, then it had to be stronger, and
it had a component of 20N in the direction of the motion.

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g Two masses are involved in a collision on an axis (one dimensional). One mass is six times the mass of the second. Both masses
statuscvo [17]

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v₁f = 0.5714 m/s   (→)

v₂f = 2.5714 m/s   (→)

e = 1  

It was a perfectly elastic collision.

Explanation:

m₁ = m

m₂ = 6m₁ = 6m

v₁i = 4 m/s

v₂i = 2 m/s

v₁f = ((m₁ – m₂) / (m₁ + m₂)) v₁i +  ((2m₂) / (m₁ + m₂)) v₂i

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v₁f = 0.5714 m/s   (→)

v₂f = ((2m₁) / (m₁ + m₂)) v₁i +  ((m₂ – m₁) / (m₁ + m₂)) v₂i

v₂f = ((2m) / (m + 6m)) * (4) + ((6m -m) / (m + 6m)) * (2)

v₂f = 2.5714 m/s   (→)

e = - (v₁f - v₂f) / (v₁i - v₂i)   ⇒   e = - (0.5714 - 2.5714) / (4 - 2) = 1  

It was a perfectly elastic collision.

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SOVA2 [1]

Answer:

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Explanation:

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The magnetic field around a magnet is called<br> Plss tell me fasssttt
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