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2 years ago

15

Suppose a 4,000-kg elephant is hoisted 20 m above Earth’s surface. What will the elephant’s gravitational potential energy be? (

Show your work in the space below.)

2 answers:

Len [333]2 years ago

5 0

Answer: 784000 J or 784 KJ

Explanation:

U = m * g * h

U = 4000 * 9.8 * 20

U = 784000 J

Hope this was helpful:D

Iteru [2.4K]2 years ago

3 0

Answer: 784000 J

Explanation:

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B . unequal heating of the Earth's surface by the sun

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Katrina’s recipe for orange muffins calls for 400 grams of flour. How many kilograms of flour are in the recipe?

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0.4 Kilograms of flour

Explanation:

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If you are in a car and your sibling is driving in the same car next to you at the same speed, does your brother appear to be mo

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2 years ago

You have a stopped pipe of adjustable length close to a taut 62.0-cm, 7.25-g wire under a tension of 3910 N . You want to adjust

Ber [7]

Answer:

L = 6 cm

Explanation:

Second overtone of the wire is same as third harmonic

so its frequency is given as

$f = \frac{3}{2L}\sqrt{\frac{T}{\mu}}$

here we know that

$\mu = \frac{M}{L}$

$\mu = \frac{7.25 \times 10^{-3}}{0.62}$

$\mu = 0.0117 kg/m$

now we have

$f = \frac{3}{2\times 0.62}\sqrt{\frac{3910}{0.0117}}$

$f = 1398.6 Hz$

Now fundamental frequency of sound in a pipe is given as

$f = \frac{v}{4L}$

$1398.6 = \frac{340}{4L}$

$L = 0.06 m$

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7 0

3 years ago

A baseball of radius r = 5.2 cm is at room temperature T = 20.8 C. The baseball has emissivity of ε = 0.86 and the Stefan-Boltzm

Marrrta [24]

Answer:

$P = 12.37 \frac{J}{s} = 12.37 Watts$

Explanation:

Previous concepts

The Thermal radiation is one of "3 mechanisms who allows to bodies exchange energy".

The thermal radiation formula is given by:

$\frac{P}{A} = \epsilon \sigma T^4$

Where $\sigma = 5.67 x10^{-8} \frac{J}{sm^2 K^4}$

If we solve for P we got:

$P = A \epsilon \sigma T^4$

Since we have a baseball ball considered as a sphere the superficial area is given by:

$A = 4\pi r^2$

Solution to the problem

And if we replace this into our equation of P we got:

$P = (4\pi r^2) \epsilon \sigma T^4$

And we can reorder this like that:

$P = 4 \epsilon \pi \sigma r^2 T^4$

We can convert the radius to meters and we got:

$r= 5.2 cm*\frac{1m}{100 cm}=0.052 m$

Now we can convert the temperature to Kelvin and we got:

$T = 20.8 +273.15 = 293.95 K$

$\epsilon = 0.86$ the emissivity given

And now we can replace into the formula for P and we got:

$P = 4*0.86*\pi *(5.67x10^{-8} \frac{J}{s m^2 K^4}) (0.052m)^2 (293.95 K)^4$

$P = 12.37 \frac{J}{s} = 12.37 Watts$

6 0

3 years ago