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Savatey [412]
3 years ago
14

What is the normal force acting on a 65 kg desk?

Physics
1 answer:
Aneli [31]3 years ago
4 0

Normal force is an equal but opposite force to weight.

Weight = Normal force

weight=m×g

= 65×10

=650N

Explanation:

HOPE THAT THIS IS HELPFUL.

HAVE A GREAT DAY.

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Complete the sentence below using one of the following
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Answer:

equilibrium

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A baseball is thrown at an angle of 40.0° above
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Vector trigonometry can be used for this problem. Since the horizontal component is 12 meters per second, this is technically the hypotenuse (actual initial velocity) multiplied to cosine of 40 degrees. Therefore, to find the hypotenuse, we must divide 12 by cosine 40degrees. cos(40)= 0.766, and 12/0.766 = approximately 15.664, therefore our answer is (3) 15.7 m/s
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If the magnification produced by a lens has a negative value, the image will be
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Which of the following scenarios would be optimal for obtaining a date from radioactive decay using these isotopes: 87Rb, 147Sm,
REY [17]

Answer:

a) 238U, 40K and 87Rb, b)   235U and to a lesser extent 40K , c)  he 235U,

d) possibility is 14C , e)this period would be ideal for 14C , f) 14C should be used since it is the one with the least average life time, even though the measurements must be very careful

Explanation:

One of the applications of radioactive decay is the dating of different systems.

To do this, the quantity of radioactive material in a meter is determined and with the average life time, the time of the sample is found.

Let's write the half-life times of the given materials

87Rb T ½ = 4.75 1010 years

147Sm T ½ = 1.06 1011 years

235U = 7,038 108 years

238U = 4.47 109 years

40K = 1,248 109 years

14C = 5,568 103 years

we already have the half-life of the different elements given

a) meteors. As these decomposed in the formation of the solar system, their life time is around 3 109 to 5 109 years, so it is necessary to look for elements that have a life time of this order, among the candidates we have 238U, 40K and 87Rb if these elements were at the moment of the formation of these meteors, there must still be rations in them, instead elements 14C already completely adequate

b) rock. The formation period is 4.20-108 years, therefore one of the most promising elements is 235U and to a lesser extent 40K since it is more abundant in rocks. The other elements with higher life times have not decayed and therefore will not give a true value and the 14C is completely decayed

c) volcanic ash. Formation time 6107 years, the only element that has the possibility of having a count is the 235U, the others have a life time so long that they have not decayed and the 14C is complete, unbent

d) scarp of an earthquake formation time 5 101 years, The only one that has any possibility is 14C even when it has declined very little, all the others, you have time to long that has not decayed

e) INCA excavation. The time of this civilization is about 10000 to 500 years (104 to 5 102 years), we see that this period would be ideal for 14C since it has some period of cementation, the others have not decayed

f) Tree in Blepharitis. 14C should be used since it is the one with the least average life time, even though the measurements must be very careful because of a period of disintegration. We have such a long time that they have not decayed

8 0
4 years ago
A researcher studying the nutritional value of a new candy places a 6.60 g 6.60 g sample of the candy inside a bomb calorimeter
cricket20 [7]

Answer:

there are 3.018 kcal= 3018 cal per gram of candy

Explanation:

If the assume that the calorimeter is perfectly insulated, then all the heat released by the combustion is absorbed by the calorimeter.

Also knowing that Q= C * ΔT , where C= heat capacity of the calorimeter , ΔT= temperature change , Q = heat released by the combustion of the candy

replacing values

Q = C * ΔT = 33.90 kJ/°C * 2.46°C = 83.394 kJ

since Q is the heat released when burned all the mass m of the candy, the number of calories per gram of candy will be

q = Q/m =83.394 kJ / 6.60 g = 12.635 kJ/g

q = 12.635 kJ/g * 1 kcal / 4.186 kJ = 3.018 kcal per gram of candy

7 0
3 years ago
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