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Dima020 [189]
3 years ago
12

Why is the sky blue and doesn't change color

Physics
1 answer:
Softa [21]3 years ago
7 0

The statement is <u>false</u> because the sky <u>can change </u>colors during sunsets, sun rises, etc. The sky is not always blue.

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according to newton's second law of motion of the net force acting on the object increases while the mass of the object remains
Licemer1 [7]

Answer:

The Acceleration will increase

Explanation:

Newton's Second Law of motion: It states that the rate of change of momentum is directly proportional to the applied force and takes places along the direction of the force.

It can be expressed mathematically as,

F ∝ m(v-u)/t

Where (v-u)/t = a

F  = kma.

F = force, m = mass of the body, a = acceleration, k = constant of proportionality which tend to unity for a unit force, a unit mass, and a unit acceleration.

Therefore,

F = ma.

From the equation above,

If the net force acting on a body increase, while the mass of the body remains constant, the acceleration will also increase.

4 0
3 years ago
Which particles in an atom are acted upon by the strong force? A. Electrons and neutrons B. Neutrons and protons O C. Protons an
BARSIC [14]

\large \sf \pmb{B) \: Neutrons \:  and  \: Protons}

  • <em>Neutrons And Protons</em> is a particles in an atom and are acted upon by the strong force.
6 0
2 years ago
An object of mass 20 kg is raised vertically through a distance of 8 m above ground level. If g = 10 m/s2, what is the gravitati
IgorC [24]

2400joules

Explanation:

P.E

m= 20kg h=8m g=10m

P.E= 20×8×10

=2400joules

6 0
2 years ago
Whats is your name boy and girl
azamat

Answer:

lol what.

Explanation:

7 0
3 years ago
Read 2 more answers
Consider blood (density 1025 kg/m3) flowing through an artery with circular cross section that looks like this: Ignore viscosity
Klio2033 [76]

The given question is incomplete. The complete question is attached with an image below.

Explanation:

Mass flow rate through region A will be calculated as follows.

Rate = \rho \times A \times \mu

       = \rho \times \pi \times R^{2} \times \mu

       = 1025 \times 3.14 \times (0.5 \times 10^{-2})^{2} \times 30 \times 10^{-2}

       = 24138.75 \times 10^{6} kg/s

Therefore, we can conclude that the mass flow rate through region A is 24138.75 \times 10^{6} kg/s.

8 0
3 years ago
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