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Dima020 [189]
3 years ago
12

Why is the sky blue and doesn't change color

Physics
1 answer:
Softa [21]3 years ago
7 0

The statement is <u>false</u> because the sky <u>can change </u>colors during sunsets, sun rises, etc. The sky is not always blue.

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A student measures the electric flux through a closed spherical surface of volume V to be X. She then removes the charge from in
ELEN [110]

Answer:

The student is wrong

Explanation:

According to Gauss' law, electric flux through a surface is independent of the shape of the surface. So, the same electric flux which flows through the spherical surface flows through the cylindrical surface.

4 0
4 years ago
"Ryan drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 7 hours. When Ryan drove
Flura [38]

Answer:

Distance between Ryan home and mountain will be 252 miles

Explanation:

Let the distance from home to mountains is d

It is given that it took 7 hours to go mountains from home

Let the speed in going to mountain is v

Then according to question speed in coming from mountain is v+27

And time taken in come from mountain to home is hour

As distance will be same in both case

Distance will be equal to distance=speed\times time

So v\times 7=(v+27)\times 4

3v=108

v = 36 miles per hour

So distance will be equal to d=36\times 7=252miles

8 0
4 years ago
A projectile is launched with an initial velocity 60m/s at an angle 60° to the vertical. What the magnitude of it's displacement
emmasim [6.3K]

Answer:

the magnitude of the displacement after 5s is 137.31 m.

Explanation:

Given;

initial velocity of the projectile, u = 60 m/s

angle of projection, θ = 60°

time of motion, t = 5s

the vertical component of the velocity, u_y= u\ sin \theta = 60sin(60^0)

The magnitude of the displacement after 5s is calculated as;

h = u_yt -\frac{1}{2} gt^2\\\\h = 60sin (60^0)\times 5 - \frac{1}{2} (9.8)(5)^2\\\\h = 259.81-122.5\\\\h = 137.31 \ m

Therefore, the magnitude of the displacement after 5s is 137.31 m.

3 0
3 years ago
A chair of weight 125 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F = 3
iris [78.8K]

Answer:

N = 148.10N

Explanation:

GIVEN

Weight =125 N

force = 35

angle =42°

since there is no vertical acceleration a_{y} = 0 from

free body diagram

\Sigma fa_{y} = ma_{y} = 0

N-W-Fsin42\degree = 0\\\\N= W+Fsin42\\N = 125+35\times 0.66\\N = 148.10 N

5 0
4 years ago
I need help on this question please answer within like a PLEASE QUICK HELP
Ludmilka [50]
The answer is c 5 starrrrrr
7 0
3 years ago
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