Answer:
Final mass of Argon= 2.46 kg
Explanation:
Initial mass of Argon gas ( M1 ) = 4 kg
P1 = 450 kPa
T1 = 30°C = 303 K
P2 = 200 kPa
k ( specific heat ratio of Argon ) = 1.667
assuming a reversible adiabatic process
<u>Calculate the value of the M2 </u>
Applying ideal gas equation ( PV = mRT )
P₁V / P₂V = m₁ RT₁ / m₂ RT₂
hence : m2 = P₂T₁ / P₁T₂ * m₁
= (200 * 303 ) / (450 * 219 ) * 4
= 2.46 kg
<em>Note: Calculation for T2 is attached below</em>
Answer:
are you wht
didn't understand the question
Answer:
See attachment for detailed answer.
Explanation:
Answer:
I = 8.3 Amp
potential drop = 83 V
Explanation:
Power = 100 KW
V = 12,000 V
R = 10 ohms
a)
Calculate current I in each wire:
P = I*V
I = P / V
I = 100 / 12 = 8.333 A
b)
Calculate potential drop in each wire:
V = I*R
V = (8.3) * (10)
V = 83 V