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kumpel [21]
3 years ago
5

Drop the name below the corresponding part. (Look at the picture above to answer)

Engineering
1 answer:
Vlad1618 [11]3 years ago
7 0

Answer:the answer is d

Explanation: because it is the right answer

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Tin atoms are introduced into an FCC copper ,producing an alloy with a lattice parameter of 4.7589×10-8cm and a density of 8.772
slega [8]

Answer:

atomic percentage = 143 %

Explanation:

Let  x be the number of tin atoms and there are 4 atoms / cell in the FCC structure , then 4 -x  be the number of copper atoms . Therefore, the value of x can be determined by using the density equation as shown below:

\mathbf{density (\rho) = \dfrac{(no \ of \ atoms/cell)(atomic \ mass )}{(lattice \ parameter )^3(6.022*10^{23} atoms/ mol)} }

where;

the lattice parameter is given as : 4.7589 × 10⁻⁸ cm

The atomic mass of tin is 118.69 g/mol

The atomic mass of copper is 63.54 g/mol

The density is 8.772 g/cm³

\mathbf{8.772 g/cm^3 = \dfrac{(x)(118.69 \ g/mol) +(4-x)(63.54 \ g/mol)}{(4.7589*10^{-8} cm )^3(6.022*10^{23} atoms/ mol)} }

569.32 = 118.69x + 254.16-63.54x

569.32 - 254.16 = 118.69x - 63.54 x

315.16 = 55.15x

x = 315.16/55.15

x = 5.72 atoms/cell

As there are four atoms per cell in FCC structure for the metal, thus, the atomic percentage of the tin is  calculated as follows :

atomic % = \frac{no \ of \ atoms \ per  \ cell \ in \ tin }{no \ of \ atoms \ per  \ cell \ in \ the \ metal}*100

atomic % = \frac{5.72 \ atoms / cell}{4 \ atoms/ cell} *100

atomic % = 143 %

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3 years ago
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The standard weight of copper tubing used most frequently in the heating and air-conditioning industry is
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