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ANTONII [103]
2 years ago
13

On what factors does the gravity of a planet depend ?​

Physics
2 answers:
PolarNik [594]2 years ago
6 0

Answer:

IT DEPENDS PARTICULARLY ON THE MASS OF AN OBJECT

Ray Of Light [21]2 years ago
3 0

Answer:

Gravity of a particular planet depends on the mass of the planet and the radius of the planet.

Explanation:

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Friction removes energy from objects in motion. Which statement best describes how this works?
xenn [34]

<em>friction transforms KE into thermal energy (a)</em>

That's why, if it goes on long enough, the moving object actually gets warm.

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2 years ago
How many bases are there in baseball before reaching home plate?
gregori [183]
There are 3 bases before you reach home plate.
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3 years ago
What are the reactants
Naddika [18.5K]

Answer:

The reagents correspond to substances that react with others, generating a chemical reaction.

Explanation:

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H2 + 02 -> H202

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3 years ago
A 180 cm length of string has a mass of 5.0 g. it is stretched with a tension of 8.6 n between fixed supports. (a) what is the w
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5 0
3 years ago
A 100-kg spacecraft is in a circular orbit about Earth at a height h = 2RE .
maria [59]

To solve this problem it is necessary to apply the concepts related to the conservation of the Gravitational Force and the centripetal force by equilibrium,

F_g = F_c

\frac{GmM}{r^2} = \frac{mv^2}{r}

Where,

m = Mass of spacecraft

M = Mass of Earth

r = Radius (Orbit)

G = Gravitational Universal Music

v = Velocity

Re-arrange to find the velocity

\frac{GM}{r^2} = \frac{v^2}{r}

\frac{GM}{r} = v^2

v = \sqrt{\frac{GM}{r}}

PART A ) The radius of the spacecraft's orbit is 2 times the radius of the earth, that is, considering the center of the earth, the spacecraft is 3 times at that distance. Replacing then,

v = \sqrt{\frac{(6.67*10^{-11})(5.97*10^{24})}{3*(6.371*10^6)}}

v = 4564.42m/s

From the speed it is possible to use find the formula, so

T = \frac{2\pi r}{v}

T = \frac{2\pi (6.371*10^6)}{4564.42}

T = 8770.05s\approx 146min\approx 2.4hour

Therefore the orbital period of the spacecraft is 2 hours and 24 minutes.

PART B) To find the kinetic energy we simply apply the definition of kinetic energy on the ship, which is

KE = \frac{1}{2} mv^2

KE = \frac{1}{2} (100)(4564.42)^2

KE = 1.0416*10^9J

Therefore the kinetic energy of the Spacecraft is 1.04 Gigajules.

8 0
2 years ago
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