Answer: Option (C) is the correct answer.
Explanation:
It is given that total mass is 1 kg and quality is 50%. Hence, the weight of liquid and vapor is 0.5 kg each.
Since, temperature is given as = (25 + 273.15) K = 298.15 K
Molecular mass of water = 18 g/mol
Therefore, calculate the number of moles of water as follows.
No. of moles of water vapor =
= (as 1 kg = 1000 g, so 0.5 kg = = 500 g)
= 27.78 mol
This will also be equal to the number of moles of liquid water present.
According to the steam tables, water exists in its saturated state at at a pressure or 3170 Pa.
Hence, on assuming ideal gas behavior of the vapor the equation will be as follows.
=
= 21.72
Whereas we will calculate the volume of liquid water as follows.
Volume =
=
= 0.5 L
As 1 L = 0.001 . So, 0.5 L = 0.0005 .
Therefore, total volume = Volume of vapor + volume of liquid water
= 21.72 + 0.0005
= 21.7205
= 22 (approx)
Thus, we can conclude that volume occupied by the water (vapor liquid) is 22 .