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Korvikt [17]
3 years ago
15

For the element barium, which wavelength of light is produced by the largest drop in energy for an electron? Which represents th

e smallest drop? Explain.
Chemistry
1 answer:
Dvinal [7]3 years ago
3 0
For such calculation, we apply Planck's equation:
E = nhc / λ; where n is the number of photons, h is the Planck's constant, c is the speed of light and λ is the wavelength of the light.
As is visible from the equation, energy and wavelength have an inverse relationship. Therefore, larger energy drops produce smaller wavelengths and smaller drops produce larger wavelengths.
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When 3.51 g of phosphorus was burned in chlorine, the product was a phosphorus chloride. Its vapor took 1.77 times as long to ef
kumpel [21]

Answer:

<em>molar mass of the phosphorus chloride = 138.06 g/mol</em>

<em></em>

Explanation:

<em>mass of phosphorus will be the same as mass of CO2, since it is stated that they are of equal amount.</em>

mass = 3.51 g

<em>lets assume that it took the CO2 1 sec to effuse, then the time taken by the phosphorus chloride will be 1.77 sec</em>

From this we can say that

rate of effusion of CO2 = 3.51/1 = 3.51 g/s

rate of effusion of the phosphorus chloride = 3.51/1.77 = 1.98 g/s

<em>From graham's equation of effusion</em>,

\frac{Rc}{Rp} = \sqrt{\frac{Mp\\}{Mc} }

Rc = rate of effusion of CO2 = 3.51 g/s

Rp = rate of effusion of phosphorus chloride = 1.98 g/s

Mc = molar mass of CO2 = 44.01 g/mol

Mp = molar mass of the phosphorus chloride = ?

Imputing values into the equation, we have

\frac{3.51}{1.98} = \sqrt{\frac{Mp\\}{44.01} }

1.77 = \frac{\sqrt{Mp} }{6.64}

11.75 = \sqrt{Mp}

Mp = 11.75^{2}

Mp = <em>molar mass of the phosphorus chloride = 138.06 g/mol</em>

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Answer:

should be D

Explanation:

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A compound that yields hydrogen ions when dissolved in a solution is an acid.

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Mixture is the answer 
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