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soldier1979 [14.2K]
3 years ago
8

5. Which are forms of energy? Select all that apply.

Chemistry
1 answer:
slavikrds [6]3 years ago
4 0

Answer:

There are mechanical energies. These consist of kinetic energy and gravitational potential energy.

Kinetic energy is the energy an object contains when it is in motion. Ex.: A car moving, a ball falling off of a building.

Gravitational potential energy is the potential for an object to do work at a certain height. If a 1 kg ball is placed 1 meter high, it has 9.8 Joules of potential energy, represented with the equation, Ug=mgh.

There are Non-Mechical Energies, which I assume you are trying to get. There is Thermal Energy, Electrical Energy, Light, Sound, Nuclear Energy, and Chemical Energy.

Thermal Energy is essentially heat. Friction causes thermal energy.

Electrical energy is potential difference. It is the work that can be done by a point charge.

Nuclear energy is like fission and fusion

Chemical energy is energy from chemical processses. Think, photosynthesis for example.

Sound is molecules hitting other molecules. It occurs a lot with friction as well.

Light is, well, you know what light is.

Explanation:

please let me know.. hope It helps you

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In which set do all elements tend to form anions in binary ionic compounds? li, na, k n, o, i c, s, pb k, fe, br?
pav-90 [236]

Atoms or molecule after gaining of electron possesses negative charge and is known as anion.

For the given sets:

  • Li, Na, K

The given elements are alkali metals and have tendency to lose electrons easily and form cations.

  • N, O, I

The given elements are non-metals and are electronegative. So, they gain electrons easily and form anion.

  • C, S, Pb

Carbon has tendency to form bond by sharing of electrons, Sulfur has tendency to gain electrons and form anion whereas Lead has tendency to lose electron.

  • K, Fe, Br

Potassium and Iron has tendency to lose electron and form cation whereas Bromine has tendency to gain electron to form anion.

Hence, from the given sets, all elements of set: N, O, I have tendency to form anions in binary ionic compounds.

8 0
3 years ago
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What kinds of energy does the Sun provide earth
AysviL [449]
 I am positive it is solar energy
 

5 0
3 years ago
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15 POINTS PLEASE HELP
Lapatulllka [165]

Answer:

Neutrons = ( Atomic mass – Atomic number ) ( A–Z )

Protons and Electrons are equal to the atomic number

For example Neon,

Mass number (A) = 20

Atomic Number (Z) = 10

Number of Protons = 10

Number of Electrons = 10

Number of Neutrons = ( A–Z ) = 10

Electronic distribution :

K= 2

L= 8

4 0
3 years ago
According to Boyle’s law, when the pressure on a gas increases at constant temperature, its volume
gladu [14]
The answer is c. decreases. The gas law has a rule of P1V1=P2V2. So when the pressure of this gas increases, the volume will decrease.
8 0
3 years ago
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Determine the rate law and the value of k for the following reaction using the data provided.
blsea [12.9K]

<u>Answer:</u> The rate law expression is \text{Rate}=k[NO]^2[O_2]^1 and value of 'k' is 1.727\times 10^3M^{-2}s^{-1}

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

2NO(g)+O_2(g)\rightarrow 2NO_2(g)

Rate law expression for the reaction:

\text{Rate}=k[NO]^a[O_2]^b

where,

a = order with respect to nitrogen monoxide

b = order with respect to oxygen

  • <u>Expression for rate law for first observation:</u>

8.55\times 10^{-3}=k(0.030)^a(0.0055)^b       ....(1)

  • <u>Expression for rate law for second observation:</u>

1.71\times 10^{-2}=k(0.030)^a(0.0110)^b       ....(2)

  • <u>Expression for rate law for third observation:</u>

3.42\times 10^{-2}=k(0.060)^a(0.0055)^b      ....(3)

Dividing 1 from 2, we get:

\frac{1.71\times 10^{-2}}{8.55\times 10^{-3}}=\frac{(0.030)^a(0.0110)^b}{(0.030)^a(0.0055)^b}\\\\2=2^b\\b=1

Dividing 1 from 3, we get:

\frac{3.42\times 10^{-2}}{8.55\times 10^{-3}}=\frac{(0.060)^a(0.0055)^b}{(0.030)^a(0.0055)^b}\\\\2^2=2^a\\a=2

Thus, the rate law becomes:

\text{Rate}=k[NO]^2[O_2]^1

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

8.55\times 10^{-3}=k[0.030]^2[0.0055]^1\\\\k=1.727\times 10^3M^{-2}s^{-1}

Hence, the rate law expression is \text{Rate}=k[NO]^2[O_2]^1 and value of 'k' is 1.727\times 10^3M^{-2}s^{-1}

4 0
3 years ago
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