Answer:
![1.4007\times 10^{-8}\ N](https://tex.z-dn.net/?f=1.4007%5Ctimes%2010%5E%7B-8%7D%5C%20N)
![1.50075\times 10^{-6}\ N](https://tex.z-dn.net/?f=1.50075%5Ctimes%2010%5E%7B-6%7D%5C%20N)
![0.000000667\ N](https://tex.z-dn.net/?f=0.000000667%5C%20N)
Explanation:
= Mass of baby = 3 kg
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
r = Distance between objects
Gravitational force of attraction is given by
![F=\dfrac{Gm_1m_2}{r^2}\\\Rightarrow F=\dfrac{6.67\times 10^{-11}\times 70\times 3}{1^2}\\\Rightarrow F=1.4007\times 10^{-8}\ N](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7BGm_1m_2%7D%7Br%5E2%7D%5C%5C%5CRightarrow%20F%3D%5Cdfrac%7B6.67%5Ctimes%2010%5E%7B-11%7D%5Ctimes%2070%5Ctimes%203%7D%7B1%5E2%7D%5C%5C%5CRightarrow%20F%3D1.4007%5Ctimes%2010%5E%7B-8%7D%5C%20N)
The force between baby and obstetrician is ![1.4007\times 10^{-8}\ N](https://tex.z-dn.net/?f=1.4007%5Ctimes%2010%5E%7B-8%7D%5C%20N)
![F=\dfrac{6.67\times 10^{-11}\times 3\times 2.7\times 10^{27}}{(6\times 10^{11})^2}\\\Rightarrow F=1.50075\times 10^{-6}\ N](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7B6.67%5Ctimes%2010%5E%7B-11%7D%5Ctimes%203%5Ctimes%202.7%5Ctimes%2010%5E%7B27%7D%7D%7B%286%5Ctimes%2010%5E%7B11%7D%29%5E2%7D%5C%5C%5CRightarrow%20F%3D1.50075%5Ctimes%2010%5E%7B-6%7D%5C%20N)
The force between the baby and Jupiter is ![1.50075\times 10^{-6}\ N](https://tex.z-dn.net/?f=1.50075%5Ctimes%2010%5E%7B-6%7D%5C%20N)
![F=\dfrac{6.67\times 10^{-11}\times 3\times 2.7\times 10^{27}}{(9\times 10^{11})^2}\\\Rightarrow F=0.000000667\ N](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7B6.67%5Ctimes%2010%5E%7B-11%7D%5Ctimes%203%5Ctimes%202.7%5Ctimes%2010%5E%7B27%7D%7D%7B%289%5Ctimes%2010%5E%7B11%7D%29%5E2%7D%5C%5C%5CRightarrow%20F%3D0.000000667%5C%20N)
The force between the baby and Jupiter is ![0.000000667\ N](https://tex.z-dn.net/?f=0.000000667%5C%20N)
Answer:
They will run parallel to each other as the none of a straight pole cannot be bent in such a way where one side can turn without the other turning.
1.) Use the formula to solve -
1/f = 1/do + 1/di; Where f = focal length; 1/do + 1/di
1/f = 1/do + di
1/8 = 1/25 + 1/?
.125 = .04 + 1/di
.125 -.04 = 1/di (transferred .04 to the left side of the equation)
.085/1 = 1/di
.085di/.085 = 1/.085 (multiplied both sides by di and divided both sides by .085)
di = 11.76 or 12
2.) Therefore, 12 cm is the distance from the image to the mirror
This is 7e-5 meters. Hope this helps! Please mark brainliest. :)