At STP 32 g of O₂ would occupy by the same volume as 4 g of He
<h3>Further explanation</h3>Complete question
At STP 32 g of O₂ would occupy by the same volume as:
- 4.0 g of He
- 8.0 g of CH₄
- 64 g of H₂
- 32 g of SO₂
Standard Conditions
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.
So the gas will have the same volume if the number of moles is the same
mol of 32 grams of O₂ :
- He
- CH₄
- H₂
- SO₂
<em>So mol of 4 g He = mol of 32 g O₂</em>