It protects in the food and other things in our everyday society
Answer:
1.24 C
Explanation:
We know that the magnitude of the induced emf, ε = -ΔΦ/Δt where Φ = magnetic flux and t = time. Now ΔΦ = Δ(AB) = AΔB where A = area of coil and change in magnetic flux = Now ΔB = 0 - 0.750 T = -0.750 T, since the magnetic field changes from 0.750 T to 0 T.
The are , A of the circular loop is πD²/4 where D = diameter of circular loop = 16.7 cm = 16.7 × 10⁻²m
So, ε = -ΔΦ/Δt = -AΔB/Δt= -πD²/4 × -0.750 T/Δt = 0.750πD²/4Δt.
Also, the induced emf ε = iR where i = current in the coil and R = resistance of wire = ρl/A where ρ = resistivity of copper wire =1.68 × 10⁻⁸ Ωm, l = length of wire = πD and A = cross-sectional area of wire = πd²/4 where d = diameter of wire = 2.25 mm = 2.25 × 10⁻³ m.
So, ε = iR = iρl/A = iρπD/πd²/4 = 4iρD/d²
So, 4iρD/d² = 0.750πD²/4Δt.
iΔt = 0.750πD²/4 ÷ 4iρD/d²
iΔt = 0.750πD²d²/16ρ.
So the charge Q = iΔt
= 0.750π(Dd)²/16ρ
= 0.750π(16.7 × 10⁻²m 2.25 × 10⁻³ m)²/16(1.68 × 10⁻⁸ Ωm)
= 123.76 × 10⁻² C
= 1.2376 C
≅ 1.24 C
Answer: M^-1 L^-3T^4A^2
Explanation:
From coloumb's law
K = q1q2 / (F × r^2)
Where;
q1, q2 = charges
k = constant (permittivity of free space)
r = distance
Charge (q) = current(A) × time(T) = TA
THEREFORE,
q1q2 = (TA) × (TA) = (TA)^2
Velocity = Distance(L) / time(T) = L/T
Acceleration = change in Velocity(L/T) / time (T)
Therefore, acceleration = LT^-2
Force(F) = Mass(M) × acceleration (LT^-2)
Force(F) = MLT^-2
Distance(r^2) = L^2
From ; K = q1q2 / (F × r^2)
K = (TA)^2 / (MLT^-2) (L^2)
K = T^2A^2M^-1L^-1T^2 L^-2
COLLEXTING LIKE TERMS
T^2+2 A^2 M^-1 L^-1-2
M^-1 L^-3T^4A^2
The answer would 0. The reasoning of this is because freezing point in celsius is always 0 degrees but in fahrenheit the freezing point is 32 degrees.
Answer: true
Explanation: If the mass of an object is increased so is the gravitational pull