Answer:
The total time of the projectile, is. t = 12.43 s
Explanation:
Given data,
The height from which the object is projected, h = 45 m
The initial velocity of the projectile, v = 30 m/s
The time of flight of the projectile to attain maximum height,
t₁ = u/g
= 30 / 9.8
= 3.06 s
The maximum height of the projectile,
hₓ = u²/2g
= 30²/ (2 x 9.8)
= 45.92 m
To find the time taken by the projectile to reach the ground from hₓ, using the II equation of motion.
s = ut₂ + ½ gt₂²
t₂ = √(2s/g) (∵ u = 0 at hₓ)
= √(2 x 45.92 / 9.8)
= 9.37 s
Therefore the total time of the projectile,
t = t₁ + t₂
t = 3.06 s + 9.37 s
= 12.43 s
Hence, the total time of the projectile, is. t = 12.43 s
Answer:
Answer is: hydroxyl group (-OH). A functional group is a group of atoms that determines many of the properties of an organic molecule. Functional group for alcohol is hydroxyl group or hydroxy group (-OH). In organic chemistry, alcohol and carboxylic acids contain hydroxy groups
Explanation:
Hope it helps! Correct me if I am wrong :>
Answer:
The rate of change of the height is - 4 ft/s
Solution:
As per the question:
Height of the person, y = 5 ft
The rate at which the person walks away,
Distance of the spotlight from the wall, x = 40 ft
Now,
To calculate the rate of change in the height, of the person when, x = 10 m:
From fig 1.
xy = 200 (1)
Differentiating the above eqn w.r.t time t:
Thus
(2)
From eqn (1):
When x = 10 ft
10y = 200
y = 20 ft
Using eqn (2):