Answer:
a = 1 m/s^2
Explanation:
if we assume that right is the positive x direction and y is the negative x-direction then we get:
Fr = 8N
Fl = -3N
We then find the net force acting upon the object
Ft = Fr + Fl
Ft = 8N - 3N
Ft = 5N
After we find net force acting upon the object we can then use Newton's 2nd Law to find its acceleration.
Ft = m*a
Isolate accerleration
a = Ft / m
a = 5N / 5kg
a = 1 m/s^2
Explanation:
Displacement=Velocity×time
=24.7×16.00
=395.2m
Therefore the displacement within the time interval is 395.2m
Answer:
The height of the ball, h = 81.63 m
The velocity of the ball at the highest point is zero
Explanation:
Given data,
The mass of the ball, m = 1 kg
The initial velocity of the ball, u = 40 m/s
Using the conservation of energy, the total mechanical energy of the ball initially at u = 40 m/s
E = P.E + K.E
E = 0 + ½ mv²
= ½ x 1 x 40²
= 800 J
The maximum height the ball reaches with the energy E = 20 J
The K.E of the ball is zero at the maximum height
E = mgh
h = E / mg
= 800 / (1 x 9.8)
= 81.63 m
The height of the ball, h = 81.63 m
The velocity of the ball at the highest point is zero.
Answer:
Action and reaction are the same
Explanation:
Let us carefully analyze the situation in the context of Newton's third law, when the car hits the mosquito exerts a force that acts on the mosquito, ACTION and the mosquito responds to the force that is being applied with a force of equal magnitude and direction or opposite applied to the car (Reaction).
Consequently, the correct answer is: The force of the car on the mosquito is of the same magnitude as that of the mosquito on the car