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Nata [24]
2 years ago
10

Does one of the planets spin backwards on its axis compared to the rest of the planets

Physics
1 answer:
mojhsa [17]2 years ago
4 0
Yes they do because they just have to
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You pull a wagon with a force of 20 N. The wagon has a mass of 10 kg. What is the wagon's acceleration?
Nana76 [90]

Answer:

<h3>The answer is 2 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

where

f is the force

m is the mass

From the question

f = 20 N

m = 10 kg

We have

a =  \frac{20}{10}  \\

We have the final answer as

<h3>2 m/s²</h3>

Hope this helps you

5 0
2 years ago
What is the force measured in Newtons between a proton and an electron in the ground state?
goldenfox [79]
The answer is zero hope I helped
5 0
3 years ago
What is the speed of a bobsled whose distance-time graph indicates that it traveled 124m in 26s
krek1111 [17]
It's average speed during that 26 seconds was about 4.77 m/s. Without seeing the graph, we can't tell if it was going faster or slower at any particular time during that period. All we can tell is its average for the full interval.
5 0
3 years ago
Which approach would be the most interested in studying Phineas Gage
viva [34]
Biological because its studies the function of the brain’s lobes
7 0
2 years ago
Find the value of F1 + F2 + F3.<br>​
Dovator [93]

Answer:

F = 0.78[N]

Explanation:

The given values correspond to forces, we must remember or take into account that the forces are vector quantities, that is, they have magnitude and direction. Since we have two X-Y coordinate axes (two-dimensional), we are going to decompose each of the forces into the X & y components.

<u>For F₁</u>

<u />F_{y}=2[N]<u />

<u>For F₂</u>

F_{x}=2*cos(60)\\F_{x}=1[N]\\F_{y}=-2*sin(60)\\F_{y}=-1.73[N]

<u>For F₃</u>

<u />F_{x}=-1*sin(60)\\F_{x}=-0.866[N]\\F_{y}=1*cos(60)\\F_{y}=0.5 [N]<u />

Now we can sum each one of the forces in the given axes:

F_{x}=1-0.866=0.134[N]\\F_{y}=2-1.73+0.5\\F_{y}=0.77[N]

Now using the Pythagorean theorem we can find the total force.

F=\sqrt{(0.134)^{2} +(0.77)^{2}}\\F= 0.78[N]

8 0
2 years ago
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