Answer: The initial temperature was 263 K
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = 0.939 atm
= final pressure of gas = 1.00 atm
= initial volume of gas = 9.40 L
= final volume of gas = 10.0 L
= initial temperature of gas = ?
= final temperature of gas = 
Now put all the given values in the above equation, we get:
Thus the initial temperature was 263 K
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Answer:
d≈ 1.15 g/cm^3
Explanation:
The density of an object can be found by dividing the mass over the volume.
d= m/v
The mass of the object is 54.3 grams and the volume is 47.18 cubic centimeters.
m= 54.3 g
v= 47.18 cm^3
Substitute the values into the formula.
d= 54.3 g/ 47.18 cm
Divide.
d= 1.150911403136922 g/cm^3
Let’s round to the nearest hundredth. The 0 in the thousandth place tells us to leave the 5 in the hundredth place.
d ≈ 1.15 g/cm^3
The density is about 1.15 grams per cubic centimeter.
Based on the dilution formula, 0.1 mL of the stock solution of the enzyme is required to prepare a 50-fold diluted enzyme in 0.01 M HCl.
<h3>How can 50-fold dilution of the enzyme be done?</h3>
The 50-fold dilution of the stock enzyme solution can be done by using the dilution formula to determine the given volume of the stock solution required.
The dilution formula is given below:
where:
- C1 = Initial concentration of enzyme
- C2 = Final concentration of enzyme
- V1 = Initial volume
- V2 = Final volume
From the given data for the enzyme dilution;
C1 = 1
C2 = 1/50 = 0.02
V1 = x
V2 = 5 ml
Making V1 subject of formula in the dilution formula:
V1 = C2V2/C1
V1 = 0.02 * 5/1 = 0.1 mL
Therefore, 0.1 mL of the stock solution of the enzyme is required to prepare a 50-fold diluted enzyme in 0.01 M HCl.
Learn more about dilution at: brainly.com/question/24709069
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Answer:
element
Explanation:
we know that helium is a pure substance although helium atoms are sometimes mixed with their isotopes it is still the same element. since there is no other element combined with helium this makes it an element.
