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zvonat [6]
3 years ago
6

a line k passes through the points-7,-14 and 1,26 a second line h passes through points -4,-25 and 4,15. is line k parallel to l

ine h? why or why not?
Mathematics
1 answer:
Verizon [17]3 years ago
8 0
See, pls, the following:
<u>WAY №1</u> (based on properties of lines)
1) it is possible to find out an equation for line 'k' using its points (common equation for line is y=ax+b):
\left \{ {{-14=(-7)*a+b} \atop {26=1*a+b}} \right. \ =\ \textgreater \  \  \left \{{{b=21} \atop {a=5}} \right.
this means, for line 'k' y=5x+21
2) for line 'h' (the same operations):
\left \{ {{-25=-4*a+b} \atop {15=4*a+b}} \right. =\ \textgreater \  \  \left \{ {{a=5} \atop {b=-5}} \right.
equation for line 'h' is y=5x-5
The parameter 'a' for the both lines is the same, it means k║h.
<u>WAY №2.</u> (based on properties of vectors):
1) find points for vector 'k': (1--7;26--14) ⇒ (8;40).
2) to do the same for vector 'h': (4--4;15--25) ⇒ (8;40).
3) using the found points for the both vectors to compare them:
\frac{8}{8} =1 \ and \  \frac{40}{40}=1
1=1 it means the both lines are parallel.
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7 0
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Answer: 5/4

Step-by-step explanation:

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