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2 years ago

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A woman with a mass of 60 kg climbs a set of stairs that are 3m high How much gravitational potential energy does she gain a res

ult of the climb?
Pls show your solution..

2 answers:

nikdorinn [45]2 years ago

7 0

Explanation:

a woman with a mass of 60 kg climbs a set of stairs that are 3m high How much gravitational potential energy does she gain a result of the climb?

Pls show your solution..

Serjik [45]2 years ago

3 0

Since,

P.Eg = mgh

m= 60kg

g = 9.8 m/s²

h = 3m

P.Eg = 60*9.8*3

P.Eg = 1764J or 1.764KJ

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Answer: $2.89\approx 2.9^{\circ}C/s$

Explanation:

Given

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mass of core $\left ( m\right )=1.60\times 10^5 kg$

Average specific heat $\left ( C\right )=0.3349 KJ/kg^{\circ}C$

And rate of increase of temperature = $\frac{\mathrm{d}T}{\mathrm{d} t}$

Now

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When an unbalanced force acts on an object the change in the object state of rest or motion depends on the size and direction of the force.

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Explanation:

Given that,

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The focal length of the lens is 35.52.

(B). Given that,

Object distance = 95 cm

Focal length = 29 cm

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Using formula of lens

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}$

Put the value in to the formula

$\dfrac{1}{-29}=\dfrac{1}{v}-\dfrac{1}{95}$

$\dfrac{1}{v}=\dfrac{1}{-29}-\dfrac{1}{95}$

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3 years ago

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<h2>Answer: 0.17</h2>

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Where:

$P=300J/min=5J/s=5W$ is the energy radiated by a blackbody radiator per second, per unit area (in Watts). Knowing $1W=\frac{1Joule}{second}=1\frac{J}{s}$

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Where $\epsilon$ is the body's emissivity

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Solving:

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