All categories

3 years ago

To what volume should 25ml of 15m nitric acid be diluted to prepare a 3m solution

Chemistry

1 answer:

Maurinko [17]3 years ago

6 0

We can use the dilution formula to find the volume of the diluted solution to be prepared

c1v1 = c2v2

Where c1 is concentration and v1 is volume of the concentrated solution

And c2 is concentration and v2 is volume of the diluted solution to be prepared

Substituting the values in the equation

15 M x 25 mL = 3 M x v2

v2 = 125 mL

The 25 mL concentrated solution should be diluted with distilled water upto 125 mL to make a 3 M solution

You might be interested in

Mg(OH)2 + 2HNO3 → Mg(NO3)2 + 2H20

LenaWriter [7]

Answer:

A. 1350

You multiply 18.21HNO3* 1mol MgN2O6 * 148.30MgN2O6

Then divide it by the 2mol HNO3 to get 1350

3 0

2 years ago

How much energy in joules is released when 18.5 grams of copper cools from 285 °C<br> down to 45 °C

nadya68 [22]

Answer: 1709.4 Joules

Explanation:

The quantity of Heat Energy (Q) released on cooling a heated substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since Q = ?

M = 18.5 grams

Recall that the specific heat capacity of copper C = 0.385 J/g.C

Φ = 285°C - 45°C = 240°C

Then, Q = MCΦ

Q = 18.5grams x 0.385 J/g.C x 240°C

Q = 1709.4 Joules

Thus, 1709.4 Joules is released when copper is cooled.

5 0

2 years ago

A gas occupies 900 mL at a temperature of 27 °C. What is the volume at <br><br> 132 °C?

gayaneshka [121]

Answer:

4400 ml

Explanation:

5 0

2 years ago

Which of these is an example of a physical change ?

Gre4nikov [31]

It's 1. Melting a substance. The rest are chemical changes

8 0

3 years ago

You have just isolated a new radioactive element. If you can determine its half-life, you will win the Nobel Prize in physics. Y

lbvjy [14]

Answer: 2.58 days

Explanation:

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = ?

t = age of sample = 6 days

a = initial amount of the reactant = 1 g

a - x = amount left after decay process = 0.2 g

a) to find the rate constant

$6=\frac{2.303}{k}\log\frac{1.0}{0.2}$

$k=\frac{2.303}{6}\log\frac{1.0}{0.2}$

$k=0.268days^{-1}$

b) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

$t_{\frac{1}{2}}=\frac{0.693}{k}$

$t_{\frac{1}{2}}=\frac{0.693}{0.268}=2.58days$

The half life is 2.58 days

3 0

2 years ago