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pochemuha
2 years ago
10

Plan to refuel when your fuel gauge reads __________.

Engineering
2 answers:
lana66690 [7]2 years ago
8 0
I would start planning to refuel when the fuel gauge reads under 1/4 of a tank remaining
bazaltina [42]2 years ago
3 0

Answer:

low on fuel or if it's red

Explanation:

common sense to be honest :/

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If you replace the text value in an associative dimension, the text value will not change when the
Nostrana [21]

Answer:

C

Explanation:

7 0
3 years ago
The primary heat transfer mechanism that quickly warms my hand if I hold it directly above a campfire is: a)-Radiation b)-Induct
Tanzania [10]

Answer:

The correct answer is option 'c':Convection.

Explanation:

When we ignite a campfire the heat produced by combustion heats the air above the fire. As we know that if a gases gains heat it expands thus it's density decreases and hence it rises, if we hold our hands directly above the fire this rising hot air comes in contact with our hands thus warming them.

The situation is different if we are at some distance from the campfire laterally. Since the rising air cannot move laterally the only means the heat of the fire reaches our body is radiation.

But in the given situation the correct answer is convection.  

6 0
3 years ago
2. A
Charra [1.4K]
Answer: Projectile

Explanation:
A projectile is any object that once projected or dropped continues in motion by its own inertia and is influenced only by the downward force of gravity.
8 0
3 years ago
The convection coefficient for flow over a solid sphere may be determined by submerging the sphere, which is initially at 25 °C,
sashaice [31]

Answer:

t = 59.37 s

Explanation:

Given data:

thermal diffusivity = \alpha = \frac{k}{\rho c_p} =0.40\times 10^{-0.5}

theraml conductivity = k = 22 W/m.K

h = 300 W/ m^2.K

T_i = 25 degree C = 298 k

T_o = 60 degree C = 333 k

T_{\infty}= 75 degree C =  348 L

diameter d = 0.1 m

characteristics length Lc = r/3 = = 0.0166

Bi = \frac{hLc}{K} = \frac{300\times 0.0166}{22} = 0.226

\tau = \frac{\alpha t}{lc^2} = \frac{0.4\times 10^{-5}\times t}{0.0166^2}

\tau = 0.036 t

\frac{T_o -T_{\infty}}{T_i -T_{\infty}} = Ae^[\lambda^2 \tau}

at Bi = 0.226

Ai = 0.982

\lambda = 0.876

\frac{333348}{298-348} = 0.982e^{-0.879^2 0.036t}

0.3 = 0.982 e^{-0.2t}

0.305 = e^{-0.2t}

-1.187 = - 0.02t

t = 59.37 s

7 0
3 years ago
A length of pipe will weigh the most when
FinnZ [79.3K]

Answer:

Mark me please as brainliest

Explanation:

A length of pipe will weigh the most when O A. part dimensions are such that the pipe is in the MMC. O B. the OD and ID are at the minimum allowable limit. OC. the OD and ID are at the maximum allowable limit. OD.part dimensions are such that the pipe is in the LMC

4 0
2 years ago
Read 2 more answers
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