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Lelechka [254]
3 years ago
6

Determine the number of atoms present in 4.5 mols of Calcium

Chemistry
1 answer:
Nuetrik [128]3 years ago
8 0

Answer:

1 mole : 6,022 * 10^23  = 4.5 moles : X

X = (6.022 * 10^23 * 4.5)/1 = 2.7099 * 10^24 atoms

Explanation:

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If two elements are from the
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Answer:

The element from Group 13.

Explanation:

Following trends of the periodic table, atomic radius of the elements increase going down from the right side and decrease on its way up diagonally to the left. (sry if u can't understand me)

7 0
3 years ago
If air is 80 percent nitrogen and 20 percent oxygen by volume what is density
Evgen [1.6K]
1 mol of any gas or mix of gases at STP conditions will have a volume of 22.4 L. Since the problem doesn’t said what are the conditions I will asume that are STP condition and the volume of one mole of the mix will have a volume of 22.4 L.

You may know that density is
D=m/v

In one mole of air I will have 80% of Nitrogen (N2) and 20% oxygen (O2).

So the mass of one mole of air will be

14 x2x0.80+16x2x0.20 = 22.4 g + 6.4 g = 28.8 g

D= 28.8/22.4 = 1.28 g/L

Of course if the temperature is higher the density will be smaller because the volume of one mole will be bigger and viceversa if the temperature decrease. Also if the pressure is different than one atm the volume of a mol will change.
5 0
3 years ago
According to bohr's model of the atom in which orbitals do electrons have the least energy
sasho [114]
According to Bohr's model of the atom, the higher the orbital in which the electrons are found, the higher their energy or excitation state. Therefore, the electrons with the least amount of energy are those at the lowest orbitals, which are closer to the nucleus. 
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7 0
3 years ago
What is the molar mass of Cu(OH)2
Mice21 [21]

Answer:

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Explanation:

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TOTAL = 97.54

6 0
3 years ago
Antony was measuring the temperature of a solution when he accidentally dropped the thermometer on the floor. What should Antony
Inga [223]

Answer:

He should notify the teacher!

Explanation:

6 0
3 years ago
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