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3 years ago

Statement true about fats in food

Engineering

2 answers:

Elodia [21]3 years ago

7 0

Answer:

What that means please explain

NNADVOKAT [17]3 years ago

4 0

Answer:

Fats are important for good health and proper functioning of the body. They are a source of energy, essential fats and enhance the absorption of fat soluble vitamins. However, too much fat and/or the wrong type of fat may negatively affect our health. Fats also give foods a particular texture, appearance and flavour.

Explanation:

plzzzzzzz Mark my answer in brainlist

and follow me

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What is the increase of entropy principle?

Sonja [21]

Answer:

Explanation:

For an isolated system (one that does not exchange matter of energy with its surroundings) entropy tends to raise.

The entire universe might be considered as an isolated system, and thus the entropy of the universe tends to rise and it never lowers.

Note that this is for isolated systems, not any systems.

A certain system might have its entropy go down, but for that it must exchange energy with its surroundings, and the entropy of the surroundings will raise. The change of entropy of the surroundings plus the change of entropy of the system (remember their signs) will always be positive.

5 0

3 years ago

An ordinary egg can be approximated as a 5.5-cm-diameter sphere. The egg is initially at a uniform temperature of 8°C and is dro

Elis [28]

Answer:

thanks for the points haha

8 0

3 years ago

Which one of the following women won the American Mathematical Society Scatter Prize, a Clay Mathematics Institute Fellowship, a

AVprozaik [17]

Answer:

Option C, Maryam Mirzakhani, is the right answer.

Explanation:

Maryam Mirzakhani was a mathematician from Iran and a professor at Stanford University. Her main contribution can be seen in the "moduli spaces of Riemann surfaces" theory. For her contribution to mathematics, she has been awarded numerous awards. These awards include the "Ruth Lyttle Satter Prize in Mathematics, a Clay Mathematics Institute Fellowship, and the Blumenthal Award". She was the first Iranian women to receive the Fields Medal.

3 0

3 years ago

A silicon carbide plate fractured in bending when a blunt load was applied to the plate center. The distance between the fractur

Amanda [17]

Question in order:

A silicon carbide plate fractures in bending when a blunt load was applied to the plate center. The distance between the fracture origin and the mirror/mist boundary on the fracture surface was 0.796 mm. To determine the stress used to break the plate, three samples of the same material were tested and produced the following. What is the estimate of the stress present at the time of fracture for the original plate?

Mirror Radius (mm) Bending Failure Stress (MPa)

0.603 225

0.203 368

0.162 442

Answer:

191 MPa

Explanation:

Failure stress of bending is Inversely proportional to the mirror radius

$Bending Stress = \frac{1}{(Mirror Radius)^{n}}$

At mirror radius 1 = 0.603 mm Bending stress 1 = 225 Mpa..............(1)

At mirror radius 2 = 0.203 mm Bending stress 2 = 368 Mpa...............(2)

At mirror radius 3 = 0.162 mm Bending stress 3 = 442 Mpa...............(3)

comparing case 1 and 2 using the above equation

$\frac{Stress 1}{Stress 2} = ({\frac{Radius 2}{Radius 1}})^{n_1}$

$\frac{225}{368} = ({\frac{0.203}{0.603}})^{n_1}$

$0.6114 = (0.3366)^{n_1}$

Taking the natural logarithm of both side

ln(0.6114) = n ln(0.3366)

n₁ = ln(0.6114)/ln(0.3366)

n₁ = 0.452

comparing case 2 and 3 using the above equation

$\frac{Stress 2}{Stress 3} = ({\frac{Radius 3}{Radius 2}})^{n_2}$

$\frac{368}{442} = ({\frac{0.162}{0.203}})^{n_2}$

$0.8326 = (0.7980)^{n_2}$

Taking the natural logarithm of both side

ln(0.8326) = n ln(0.7980)

n₂ = ln(0.8326)/ln(0.7980)

n₂ = 0.821

comparing case 1 and 3 using the above equation

$\frac{Stress 1}{Stress 3} = ({\frac{Radius 3}{Radius 1}})^{n_3}$

$\frac{225}{442} = ({\frac{0.162}{0.603}})^{n_3}$

$0.5090 = (0.2687)^{n_3}$

Taking the natural logarithm of both side

ln(0.5090) = n ln(0.2687)

n₃ = ln(0.5090)/ln(0.2687)

n₃ = 0.514

average for n

$n = \frac{n_1 + n_2 + n_3}{3}$

$n = \frac{0.452 +0.821 + 0.514}{3}$

n = 0.596

Hence to get bending stress x at mirror radius 0.796

$\frac{Stress x}{Stress 3} = ({\frac{Radius 3}{Radius x}})^{0.596}$

$\frac{Stress x}{225} = ({\frac{0.603}{0.796}})^{0.596}$

$\frac{Stress x}{225} = 0.8475$

stress x = 191 MPa

3 0

4 years ago

A network address of 172.16.0.0 /12 has been given. Which of the following accurately describes this network? (select one or mor

ludmilkaskok [199]

Answer:

B and E is correct.

Explanation:

Given that network address

172.16.0.0/12

This is class B network type.

The ending of this network will be 172.31.255.255

In IP version 4 there are four following type of classes

1)Class A (0-127)

2)Class B (128-191)

3)Class C (191-223)

4)Class D(224-239)

5)Class E (240-255)

Generally class A,B,C and D are used.

So our options B and E is correct.

3 0

3 years ago