Question

Consider a 0.15-mm-diameter air bubble in a liquid. Determine the pressure difference between the inside and outside of the air bubble if the surface tension at the air-liquid interface is a. 0.1 N/m. b. 0.12 N/m.

Answer 1

Answer:

a)$\Delta P= 2666.66 Pa$

b)$\Delta P= 3200 Pa$

Explanation:

Given that

Diameter ,d= 0.15 mm

We know that pressure difference is given as

$\Delta P=\dfrac{4\sigma }{d}$

Now by putting the values

When surface tension 0.1 N/m  :

The surface tension ,$\sigma=0.1\ N/m$

$\Delta P=\dfrac{4\times 0.1 }{0.15}\times 10^3\ Pa$

$\Delta P= 2666.66 Pa$

When surface tension 0.12 N/m  :

The surface tension ,$\sigma=0.12\ N/m$

$\Delta P=\dfrac{4\times 0.12 }{0.15}\times 10^3\ Pa$

$\Delta P= 3200 Pa$

a)$\Delta P= 2666.66 Pa$

b)$\Delta P= 3200 Pa$