Answer:
a) heat it from 23.0 to 78.3
q = (50.0 g) (55.3 °C) (2.46 J/g·°C) =
b) boil it at 78.3
(39.3 kJ/mol) (50.0 g / 46.0684 g/mol) =
c) sum up the answers from the two calculations above. Be sure to change the J from the first calc into kJ
Explanation:
The answer is 1/2 because of how many times does 2 go into 2 which is 1 and how many times 2 can go into 4 which is 2. So 1 would go on top and the 2 would go on the bottom
The answer for the following problem is mentioned below.
Explanation:
Given:
mass of iron (m) = 15.75 grams
heat (q) = 1097 J
initial temperature (
) = 25°C
final temperature (
) = 177°C
To find:
specific heat (c)
We know;
c = q ÷ mΔT
where;
c represents the specific heat
q represents the heat
m represents the mass
t represents the temperature
c = 
c = 0.45 J/kg°C
<u><em>Therefore the specific heat capacity of iron is 0.45 J/kg°C.</em></u>
Answer:
solid to gas is sublimation
gas to solid is deposition
liquid to gas is evaporation/boiling
the rest are correct
The correct answer is D. 88 g
Good Luck!! Hope this helps!! :)
