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Juli2301 [7.4K]
3 years ago
5

7. How do the test variables (independent variables) and outcome variables (dependent variables) in an

Chemistry
1 answer:
liraira [26]3 years ago
8 0

Answer:

The two main variables in an experiment are the independent and dependent variable. An independent variable is the variable that is changed or controlled in a scientific experiment to test the effects on the dependent variable. A dependent variable is the variable being tested and measured in a scientific experiment.

Explanation:

Hope this helps...

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Ozone (O 3) in the atmosphere can react with nitric oxide (NO): O 3(g) + NO(g) → NO 2(g) + O 2(g). Calculate the ΔG° for this re
Mandarinka [93]

Answer:

ΔG°  = 1022. 8 kJ

Explanation:

ΔH° = –199 kJ/mol

ΔS° = –4.1 J/K·mol

T = 25°C = 25 + 273 = 298K (Converting to kelvin temperature)

ΔG° = ?

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ΔG° = –199 - 298 (–4.1)

ΔG° = -199 + 1221.8

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3 years ago
How many carbon atoms are in 6 molecules of carbon dioxide?
o-na [289]

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What is true of a covalent bond? (03.03)
garri49 [273]

Answer:

I think B..

Explanation:

It is the sharing of electrons from one atom to another .

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3 years ago
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Which states of matter have particles that move independently of one another with very little attraction?
maks197457 [2]
Gas -- move very independently as compared to a liquid, for instance.

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An unknown metal sample has a mass : of 11.29. and a volume of 2 cm3. What is the : density of the unknown metal? ​
tatuchka [14]

Answer:

\boxed{\sf Density \ of \ the \ unknown \ metal = 5.645 \ g/cm^3}

Given:

Mass = 11.29 g

Volume = 2 cm³

To Find:

Density of unknown metal

Explanation:

Formula:

\boxed{ \bold{Density = \frac{Mass}{Volume}}}

Substituting value of mass & volume in the formula:

\sf \implies Density =  \frac{11.29}{2} \\  \\   \sf \implies Density =  5.645 \: g/cm^3

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3 years ago
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