(a)
<span>F= qE </span>
<span>F sin 30.0° = mg </span>
<span>= 0.0026(10) </span>
<span>= 0.026 N </span>
<span>F = 0.052 N </span>
<span>E = F/q = 0.052 / 60µ = 867 N/C </span>
<span>(b) </span>
<span>T = F cos 30.0° </span>
<span>= 0.0450 N</span>
Answer:
Mass
Explanation:
They have masses ranging from about 5 to several tens of solar masses.
D. Rutherford found that the atom consists of a small positively charged nucleus.
We use the kinematic equations,
(A)
(B)
Here, u is initial velocity, v is final velocity, a is acceleration and t is time.
Given, 
, 
and 
.
Substituting these values in equation (B), we get
.
Therefore from equation (A),
Thus, the magnitude of the boat's final velocity is 10.84 m/s and the time taken by boat to travel the distance 280 m is 51.63 s
On question 30, that is a displacement- time graph (DT). On this type of graph the gradient is equal to the velocity. B has the steepest gradient, then A and finally C
Now velocity is a vector quantity so it has a direction and speed ( speed doesn't have a fixed direction.)
on the DT graph im going to assume that movement B is a positive velocity with A and C being negative.
So by ranking these: A is the most negative, C is the least negative and B has to be the greatest as it is the only positive velocity.
Q31, The same type of graph is present, by looking at the gradients we can rank the largest and smallest velocities- speeds in the case of the question.
i'll skip my working out as its the same as before:
C, B, A and then D
the same idea as on Q30 applies to Q31 part b,
D,C,B then A
