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TEA [102]
2 years ago
9

Calculate the pressure increase at the bottom of a pool of depth 2m. Density of water=1000kg/m^3 g=10N/kg

Physics
2 answers:
Novosadov [1.4K]2 years ago
8 0
Please check the attached picture

Blababa [14]2 years ago
4 0
Pa = atmospheric pressure (look it up in units of N/m^2)
D = density of water (given as 1000 kg/m^3)
h = depth of water = 3m
g = acceleration of gravity = 9.8 m/s^2

At a depth of h (meters), the static pressure is

P(h) = Pa + Dgh

Plug in the numbers and get P(h) in units of N/m^2.
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