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TEA [102]
2 years ago
9

Calculate the pressure increase at the bottom of a pool of depth 2m. Density of water=1000kg/m^3 g=10N/kg

Physics
2 answers:
Novosadov [1.4K]2 years ago
8 0
Please check the attached picture

Blababa [14]2 years ago
4 0
Pa = atmospheric pressure (look it up in units of N/m^2)
D = density of water (given as 1000 kg/m^3)
h = depth of water = 3m
g = acceleration of gravity = 9.8 m/s^2

At a depth of h (meters), the static pressure is

P(h) = Pa + Dgh

Plug in the numbers and get P(h) in units of N/m^2.
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2. The components of vector A are given as follows:
Stella [2.4K]

Answer:

50 degree.

Explanation:

Given that the components of vector A are given as follows: Ax = 5.6 Ay = -4.7

The angle between vector A and B in the positive direction of x-axis will be achieved by using the formula:

Tan Ø = Ay/Ax

Substitute Ay and Ax into the formula above.

Tan Ø = -4.7 / 5.6

Tan Ø = -0.839

Ø = tan^-1(-0. 839)

Ø = - 40 degree

Therefore, the angle between vector A and B positive direction of x-axis will be

90 - 40 = 50 degree.

3 0
3 years ago
10. Solve the following numerical problems
frosja888 [35]

Answer:

\boxed {\boxed {\sf 120 \ Joules}}

Explanation:

Work is equal to the product of force and distance.

W=F*d

The force is 8 Newtons and the distance is 15 meters.

F= 8 \ N \\d= 15 \ m

Substitute the values into the formula.

W= 8 \ N * 15 \ m

Multiply.

W= 120 \ N*m

  • 1 Newton meter is equal to 1 Joule
  • Our answer of 120 N*m equals 120 J

W= 120 \ J

The work done is <u>120 Joules</u>

3 0
3 years ago
What is the mass of a crate if a net force of 12 N gives the crate an acceleration of 0.20 m/s2?
Veseljchak [2.6K]
A :-) for this question , we should apply
F = ma
Given - F = 12 N
a = 0.20 m/s^2
Solution -
F = ma
12 = m x 0.20
m = 12 by 0.20
m = 60 kg

.:. The mass is 60 kg.
8 0
3 years ago
Select the correct answer.
Simora [160]

Answer:

A. 2.36 Newtons

Explanation:

F = GmM/d²

F = 6.673 x 10⁻¹¹(1)(5.98 x 10²⁴) / (1.3 x 10⁷)²

F = 2.36121...

Very poor question design.

  mass of box... 1 significant digit

        distance... 2 significant digits

mass of earth... 3 significant digits

     value of G... 4 significant digits

Answer precision to 3 significant digits is not justifiable

7 0
3 years ago
1. A man walks round a park, first walking north for 80m, then turning right and walking
drek231 [11]

Answer:

Total distance travelled = 210m

Explanation:

Distance travelled = 80m + 50m + 10m + 70m

                               = 210m

8 0
3 years ago
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