Answer:
Explanation:
a ) Distance of screen (D) = 50 X 10⁻²
Wavelength of light λ = 690 x 10⁻⁹
d = width of slit
Distance between first and third dark fringe = 2 x fringe width
= 2 x λD/d = 3 x 10⁻³
d = 2 x 690 x 10⁻⁹ x 50 x 10⁻² /3 x 10⁻³ = 0.23 mm
b ) Width of central bright fringe = 2 λD/d
2 x 690 x 10⁻⁹ x 50 x 10⁻² /23 x 10⁻⁵ m
= 3 mm.
Answer:
2.98 m/s^2
Explanation:
I have done this before and it was a question on my physics test
The relationship between resistance R and resistivity
is
(1)
where L is the length of the wire and A is the cross-sectional area.
In our problem, the radius of the wire is half the diameter: r=1 mm=0.001 m, so the cross-sectional area is
The length of the wire is L=20 m and the resistance is
.
By re-arranging equation (1), we can find the resistivity of the wire:
Explanation:
the unknown resistance is 9ohm
i don't get the question really sorry