Question

In an effort to stay awake for an all-night study session, a student makes a cup of coffee by first placing a 200 WW electric immersion heater in 0.400 kgkg of water.

Answer 1

Answer:

The heat is 115478.4 J.

Explanation:

Given that,

Mass of water = 0.400 kg

Power = 200 W

Suppose, we determine how much heat must be added to the water to raise its temperature from 20.0°C to 89.0°C?

We need to calculate the heat

Using formula of heat

$Q=mc\Delta T$

Where, m = mass of water

c = specific heat

Put the value into the formula

$Q=400\times4.184\times(89-20)$

$Q=115478.4\ J$

Hence, The heat is 115478.4 J.