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IRINA_888 [86]
2 years ago
10

Can someone help me with this one

Physics
1 answer:
vladimir2022 [97]2 years ago
3 0

Answer:

<em>If it served you, give me 5 stars please, thank you!</em>

<em />

The equation of the tangent line is

E) y=−4x−8

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Consider the circular motion of a positively charged particle in the plane of this paper, due to a constant magnetic field B~ wh
barxatty [35]

Answer:

the direction of the particle is anti clockwise.

Explanation:

We know that;

- It's a positive particle

- That it's moving in a circle in a magnetic field

- We know the direction of the magnetic field

We can deduce the direction of the magnetic force because it is moving in a circle.

So the force is pointing to the centre of the circle and that's what is keeping it in that circular motion.

Since we know the direction of the magnetic field and force, we can use right hand rule to figure out the direction of the particle since the particle is positive.

Using right hand rule, the thumb which is the particle is pointing anticlockwise. So the direction of the particle is anti clockwise.

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Why does the bottom of a swimming pool always appear shallower than it actually is<br>​
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The refraction of light at the surface of water makes ponds and swimming pools appear shallower than they really are.

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3 years ago
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Contact [7]

Answer:

1. The bird close to the center

2. 4/25 of the original force.

Explanation:

1. Tangential velocity is v=w*d (in m/s), where w is the rotational speed, commonly denoted as the letter omega (in radians per second). d is the distance from the center of the rotating object to the position of where you would like to calculate the velocity (in meters).

As we can note, the furthest from the center we are calculating the velovity the higher it is, because the rotational velocity is not changing but the distance of the object with respect to the center is. If v=w*d, then the lower the d (distance) the lower the tangential velocity.

2. Take a look at the picture:

We have the basic equation for the gravitational force.

We have to forces: Fg1, which is the original force, and Fg2, the force when the mass and the distance changes.

If we consider that mass 2 didn't change (m2'=m2), mass 1 is four times its original (m1'=4*m1) and distance is 5 times the original (r'=5*r), then next step is just plugging it into the equation for Fg2.

Dividing the original force Fg1 by the new force Fg2 (notice you can just as well do the inverse, Fg2 divided by Fg1) gives us the relation between the forces, cancelling all the variables and being left only with a simple fraction!

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