Can someone help me with this one
1 answer:
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Answer:
(a)
Average velocity = < 0, 316000, 146000> m/s
(b) < 0, 2.844, 1.314 > m
Explanation:
r1 = < 0.02, 0.04, - 0.06 > m
r2 = < 0.02, 1.62, - 0.79 > m
time, t = 5 micro second = 5 x 10^-6 s
(a) Average velocity is defined as the ratio of total displacement to the total time taken.
Displacement = r = r2 - r1
r = < 0.02 - 0.02, 1.62 - 0.04, - 0.79 + 0.06 > m
r = < 0, 1.58, - 0.73 > m
So. Average velocity =
Average velocity =
Average velocity = < 0, 316000, 146000> m/s
(b)
Distance = velocity x time
Here time, t = 9 micro second
d = < 0, 316000, 146000> x 9 x 10^-6 m
d = < 0, 2.844, 1.314 > m
Answer:
decreases.
Explanation:
When the aircraft is flies from the warm air into the colder air then its speed will be decreases.
as we know that
we know mach number is constant
so that here Mach number M is expressed as
M = .............................1
here u is Local flow velocity with respect to the boundarie and v is the speed of sound in the medium
If the aircraft flies from hot air to cold air, the speed of sound in the medium will decrease. But the Mach number remains constant. Therefore, the local flow velocity relative to the boundaries also decreases.