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Lemur [1.5K]
2 years ago
15

The solubility of sodium hydrogen carbonate in water 20 degrees is 9.6 g/100 g h2o.

Chemistry
1 answer:
d1i1m1o1n [39]2 years ago
6 0

We can see from the details below that, the value of the solution's molality is 1.14 mol/Kg.

<h3>What is solubility?</h3>

The term solubility has to do with the quantity of solute that is able to dissolve in a given quantity of solvent. We have the solubility of the sodium hydrogen carbonate in water at 20 degrees as 9.6 g/100 g h2o.

Number of moles of sodium hydrogen carbonate = 9.6 g/84 g/mol = 0.114 moles

Number of moles water = 100 g /18 g/mol = 5.55 moles

Mole fraction of sodium hydrogen carbonate is obtainable by the use of the relation;

0.114 moles/0.114 moles + 5.55 moles

= 0.02

Molality of the solution = 0.114 moles/0.1 Kg = 1.14 mol/Kg

Learn more about solubility:brainly.com/question/8591226

#SPJ4

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The moles of HCl to neutralize the sodium hydroxide produced is<u> 0.0135 mole.  </u>

Neutralization or neutralization is a chemical response wherein an acid and a base react quantitatively with each other. In a reaction in water, neutralization outcomes in there being no excess of hydrogen or hydroxide ions gift in the answer.

<u>calculation:-</u>

<u />

2Na + 2H₂O  -----> 2NaOH + H₂

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