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zmey [24]
3 years ago
9

How can large hydrocarbon molecules be cracked in an oil refinery?

Chemistry
1 answer:
Sunny_sXe [5.5K]3 years ago
7 0

Explanation:

Large hydrocarbon molecules can be cracked in an oil refinery through the process of cracking. Cracking of hydrocarbons involves the use of heat, pressure and catalyst to resolve heavy hydrocarbons into simpler and more useful products.

  • Cracking of hydrocarbons is very essential in the oil refinery.
  • Cracking helps to break giant hydrocarbon molecules into simple and more useful ones.
  • Fractional distillation separates oil molecules into its different components based on their different boiling points.
  • The fractions produced a times are usually long chained and are not in high demand.
  • Catalytic cracking and thermal cracking helps to break the long chains of the heavy hydrocarbons fractions into simpler ones.

Learn more:

conversions brainly.com/question/4586309

#learnwithBrainly

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Describe two physical and two chemical changes involved in cooking. (4 points)
Ivenika [448]
Physical changes are when things get changed without altering chemical consistencies, which is melting solid butter into liquid one, or boiling water. Chemical changes are things such as caramelizing sugar when making sweets, or when carbon dioxide is created and released when baking bread.
7 0
3 years ago
Determine the concentration of H+ ions in an aqueous solution where [OH-] =2.25 × 10^-4 M. I have 29 minutes I beg u guys pls hu
mixas84 [53]

but where Is the volume in order for us to determine the concentration. since we have moles in H+ ions

then you can say

concentration = M*1000/V

6 0
3 years ago
Hydrazine (N 2 H 4 )) a rocket fuel reacts with oxygen to form nitrogen gas and water vapor . The reaction is represented with t
Drupady [299]

The mass of hydrazine (N₂H₄) required to produce 96 g of water (H₂O) is 85.4 g (Option C)

<h3>Balanced equation </h3>

N₂H₄ + O₂ —> N₂ + 2H₂O

Molar mass of N₂H₄ = (2×14) + (4×1) = 32 g/mol

Mass of N₂H₄ from the balanced equation = 1 × 32 = 32 g

Molar mass of H₂O = (2×1) + 16 = 18 g/mol

Mass of H₂O from the balanced equation = 2 × 18 = 36 g

SUMMARY

From the balanced equation above,

36 g of H₂O were produced by 32 g of N₂H₄

<h3>How to determine the mass of N₂H₄</h3>

From the balanced equation above,

36 g of H₂O were produced by 32 g of N₂H₄

Therefore,

96 g of H₂O will be produced by = (96 × 32) / 36 = 85.4 g of N₂H₄

Thus, 85.4 g of N₂H₄ is needed for the reaction

Learn more about stoichiometry:

brainly.com/question/14735801

8 0
2 years ago
Type the formula of the following compound: Aluminum nitride
evablogger [386]

The formula for that compound is AlN

6 0
3 years ago
How many moles of hydrogen ions are formed in the ionization of 0.250 moles of H2SO4?
True [87]

Answer:

The ionization of 0.250 moles of H₂SO₄ will produce 0.5 moles of H⁺ (hydrogen ion)

Explanation:

From the ionization of H₂SO₄, we have

H₂SO₄ → 2H⁺ + SO₄²⁻

Hence, at 100% yield, one mole of H₂SO₄ produces two moles of H⁺ (hydrogen ion) and one mole of SO₄²⁻ (sulphate ion), therefore, 0.250 moles of H₂SO₄ will produce 2×0.250 moles of H⁺ (hydrogen ion) or 0.5 moles of H⁺ (hydrogen ion) and 0.25 moles of SO₄²⁻ (sulphate ion).

That is; 0.250·H₂SO₄ → 0.5·H⁺ + 0.250·SO₄²⁻.

4 0
3 years ago
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