Answer:
P1 = 2.5ATM
Explanation:
V1 = 28L
T1 = 45°C = (45 + 273.15)K = 318.15K
V2 = 34L
T2 = 35°C = (35 + 273.15)K = 308.15K
P1 = ?
P2 = 2ATM
applying combined gas equation,
P1V1 / T1 = P2V2 / T2
P1*V1*T2 = P2*V2*T1
Solving for P1
P1 = P2*V2*T1 / V1*T2
P1 = (2.0 * 34 * 318.15) / (28 * 308.15)
P1 = 21634.2 / 8628.2
P1 = 2.5ATM
The initial pressure was 2.5ATM
Explanation:
- The boiling point of Potassium is most similar to the element sodium , since , both the elements belong to the same group i.e. , the group one , Hence , the most of the physical chemical properties are same , irrespective of some exceptions .
Hence , the Boiling point of Potassium and sodium are the same .
- The boiling point of Potassium is least similar to the element helium , since , both the elements belong to different groups , Since , Helium has a negative boiling point and is one of the most stable element , being a noble gas .