Answer:
Heat transfer in step 2 = 47.75 J
Explanation:
Internal energy = heat + work done
U = Q + W
In a cyclic process the total internal energy change of the system = 0.
In the process there are two steps. The total heat exchange in the process is the sum of heat exchanges in the two processes.
We have to find the heat exchange in step 2.
In step 1,
W = 1.25 J Q = -37 J
= -37 + 1.25 = -35.75 J
In step 2, the internal energy change will be negative of that in step 1.
U = 35.75 J
W = -12 J
U = Q + W
35.75 = Q -12
Q = 47.75 J
Heat transfer in step 2 = 47.75 J
Answer:
The Net reaction is
-
-
-
Explanation:
From the Question we are told that the buffers are
and 
When NaOH is added the Net ionic reaction would be
-
-
-
Answer: -
A) 3.59
Explanation: -
The number of significant figures in 2.06 = 3
The number of significant figures in 1.743 = 4
The number of significant figures in 1.00 = 3
During multiplication of significant figures, the number of significant figures in the answer would be the smallest value that is 3 in this case.
2.06 x 1.743 x 1.00 = 3.5908.
The answer to 3 significant figures is
2.06 x 1.743 x 1.00 = 3.59
Thus, Andi when performs the calculation that is shown below.
(2.06)(1.743)(1.00)
the answer be reported using the correct number of significant figures as A) 3.59
Answer:
Number 3
It is the way the earth stay a good tempercher for us.
Explanation:
Spontaneous reaction is a reaction which occurs naturally that is it has capability of proceeding in a given direction without the use of outside source of energy, while non spontaneous reaction is a reaction which require outside source of energy.drag of the appropriate item to their respective bins is a non spontaneous reaction since outside of energy is required to drag the item.
