(4) a compound is the correct answer~
Answer:
mass of CO₂ = 5.402 g
Explanation:
At STP, 1 mole of any gas takes up 22.4L of volume
Thus, 1 mole = 22.4 L
1 L = 1 mole ÷ 22.4
Therefore, 2.75 L = 2.75 mole ÷ 22.4 = 0.123 moles
Molecular weight of CO₂ = 44 g/mole
mass of CO₂ = molecular weight * number of moles = 44 g/mole * 0.123 moles
mass of CO₂ = 5.402 g
Answer:
25000 ppm
Explanation:
<em>Parts Per Million </em>is defined as the number of parts of a solute per one million parts of a solution.
ppm = (Weight of Solute / Weight of Solution) × 10⁶ ---(1)
Let us suppose that the air (solution) weights 100 grams, then 2.5 % of water vapors will have following mass,
Mass of Vapors g / 100 g × 100 = 2.5
Or,
Mass of Vapors = 2.5 × 100 / 100
Mass of Vapors = 2.5 g
Hence, mass of water vapors is 2.5 g.
Now, putting mass of water vapors and air in eq. 1,
ppm = (2.5 / 100) × 10⁶
ppm = 25000
Answer: 3.45 L carbon dioxide are produced
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 
of particles.
To calculate the moles, we use the equation:
According to stoichiometry :
5 moles of 
produce = 3 moles of 
Thus 0.257 moles of will produce=
of
Volume of 
Thus 3.45 L carbon dioxide are produced
