12 is first one 7 is 2nd one 9 is the last one
Answer:
8√3.
Step-by-step explanation:
192 = 2 * 2 * 2 * 2 * 2 * 2 * 3
The square root of the multiple of the 6 2's is 2*2*2 = 8
so √192 = 8√3.
Answer:
-9
Step-by-step explanation:
x² -16 = (x -4)(x +4)
This magnitude of this product can only be prime if one of the factors is ±1. Any other integer value of x will produce a composite number (or zero).
... For x-4 = ±1, x = 3 or 5
... For x+4 = ±1, x = -3 or -5
The values of x that are ±3 both give |x²-16| = 7, a prime.
The values of x that are ±5 both give |x²-16| = 9, not a prime.
The two values of x that are of interest are x=-3 and x=3. Their product is ...
... (-3)·(3) = -9
The line goes 3 right for every 1 down, so the gradient is -1/3
The y-intercept is +4, so the equation is actually y=-1/3x+4, so Chris is wrong.
