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Goshia [24]
3 years ago
8

How much heat is required to raise the temperature of 835g of water from 35.0°C to 65.0°C?

Chemistry
1 answer:
Anna007 [38]3 years ago
3 0

Answer:

25,050 calories.

Explanation:

A calorie is the amount of energy needed to raise the temperature of one gram of water 1 degree centigrade. If we are raising 835 grams of water 30 degrees then we multiply 835*30 to get 25,050 calories.

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Which wave corresponds to the higher-energy radiation? which wave corresponds to the higher-energy radiation? wave (b) has the h
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<span>The wave with the smaller wavelength will have the higher-energy radiation since they are inversely proportional. Also note that the height of the wave contributes to the amplitude.</span>
8 0
3 years ago
A car gets 28.0 miles/gallon of gas on the highway. What is this in<br> km/L?
lys-0071 [83]

Answer:

11.905 km/L

Explanation:

Given that,

A car gets 28.0 miles/gallon of gas on the highway.

We need to find the volume into km/L

We know that,

1 mile = 1.60934 km

Also,

1 gallon = 3.785 litre

So,

28\ \text{miles per gallon}=28\times \dfrac{1.60934\ km}{3.785\ L}\\\\=11.905\ \text{km/L}

Hence, the car get 11.905 km/L of the gas.

4 0
3 years ago
1 mole = 6.02 x 10” particles
NikAS [45]

Explanation:

I am sorry I don't know the answer

6 0
2 years ago
Help meeeeee
kolbaska11 [484]

Answer:

469.9K

Explanation:

Using Charles's law equation:

V1/T1 = V2/T2

Where;

V1 = initial volume (ml)

V2 = final volume (ml)

T1 = initial temperature (K)

T2 = final temperature (K)

Based on the information provided:

V1 = 280.0ml

V2 = 440.0 ml

T1 = 26.0°C = 26 + 273 = 299K

T2 = ?

Using V1/T1 = V2/T2

280/299 = 440/T2

0.936 = 440/T2

T2 = 440 ÷ 0.936

T2 = 469.9K

3 0
2 years ago
Part
Zielflug [23.3K]
NaOH (aq) + HCl(aq) => NaCl(aq)+ H2O(l)

Na+(aq)+ OH - (aq) + H +(aq) +Cl - (aq) + Cl- (aq)
=> Na+(aq) + Cl - (aq) + H2O(l)
H+(aq) + OH-(aq) => H2O(l)
6 0
2 years ago
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