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amm1812
3 years ago
14

How long does it take for a rotating object to speed up from 15.0 rad/s to 33.3 rad/s if it has a uniform angular acceleration o

f 3.45 rad/s2
Physics
1 answer:
Leona [35]3 years ago
3 0

Answer:

it takes 5.22 seconds

Explanation:

angular \: acceleration \:  =  \frac{angular \: velocity}{time}

t = (33.3 - 15) ÷ 3.45

t = 18 ÷ 3.45

t = 5.22 sec

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During which month is the bacteria population just under 1 million?
Thepotemich [5.8K]
D. March because it is just below the 1 million marker on the graph and it is the only one that low.
5 0
3 years ago
The angle θ is slowly increased. Write an expression for the angle at which the block begins to move in terms of μs.
Reika [66]

Answer:

tan \theta = \mu_s

Explanation:

An object is at rest along a slope if the net force acting on it is zero. The equation of the forces along the direction parallel to the slope is:

mg sin \theta - \mu_s R =0 (1)

where

mg sin \theta is the component of the weight parallel to the slope, with m being the mass of the object, g the acceleration of gravity, \theta the angle of the slope

\mu_s R is the frictional force, with \mu_s being the coefficient of friction and R the normal reaction of the incline

The equation of the forces along the direction perpendicular to the slope is

R-mg cos \theta = 0

where

R is the normal reaction

mg cos \theta is the component of the weight perpendicular to the slope

Solving for R,

R=mg cos \theta

And substituting into (1)

mg sin \theta - \mu_s mg cos \theta = 0

Re-arranging the equation,

sin \theta = \mu_s cos \theta\\\rightarrow tan \theta = \mu_s

This the condition at which the equilibrium holds: when the tangent of the angle becomes larger than the value of \mu_s, the force of friction is no longer able to balance the component of the weight parallel to the slope, and so the object starts sliding down.

4 0
4 years ago
The frequency of sound wave A is 250 Hz. Find the time period.
olga2289 [7]
Time period = 1 / frequency
Time period = 1 / 250 th of a second
7 0
4 years ago
A solid ball, a solid disk, and a hoop, all with the same mass and the same radius, are set rolling without slipping up an incli
MAXImum [283]

Answer:

d ) is the answer.

Explanation:

Let M be the mass  and R be the radius of each of ball , hoop and disc.

kinetic energy of sphere - 1/2 MV² + 1/2 I ω² ,ω is angular velocity and

V = ωR

kinetic energy of sphere - 1/2 MV² + 1/2 x 2/5 MR² ω²

= 1/2 MV² + 1/5 MR² ω²

MV² ( 1/2 + 1/5 )

= .7 MV²

kinetic energy of Disk - 1/2 MV² + 1/2 I ω² ,ω is angular velocity and

V = ωR

kinetic energy of Disk - 1/2 MV² + 1/2 x 1/2 MR² ω²

= 1/2 MV² + 1/4 MR² ω²

MV² ( 1/2 + 1/4 )

= .75 MV²

kinetic energy of Hoop - 1/2 MV² + 1/2 I ω² ,ω is angular velocity and

V = ωR

kinetic energy of hoop - 1/2 MV² + 1/2  MR² ω²

= 1/2 MV² + 1/2 MR² ω²

MV² ( 1/2 + 1/2 )

=  MV²

Kinetic energy is largest in case of hoop and least in case of sphere . So hoop will go up to the highest point and sphere will go to a height which will be least among the three.

7 0
3 years ago
a student wants to push a box of books with the mass of 50 kg in 3 m horizontally towards the location of the shelves where the
irina1246 [14]

Answer:

The work done is 360 J.

Explanation:

Given that,

Mass = 50 kg

Distance =3 m

We need to calculate the work done

The work done is equal to the product of force and displacement.

Using formula of work done

W = F\cdot d

W = Fd\cos\theta

Where, F = force

D = distance

θ = Angle between force and displacement

Put the value into the formula

W=120\times3\cos0^{\circ}

W=360\ J

Hence, The work done is 360 J.

8 0
3 years ago
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