Answer:
Explanation:
a) for shifting reactions,
Kps = ph2 pco2/pcoph20
=[h2] [co2]/[co] [h2o]
h2 + co2 + h2O + co + c3H8 = 1
it implies that
H2 + 0.09 + H2O + 0.08 + 0.05 = 1
solving the system of equation yields
H2 = 0.5308,
H2O = 0.2942
B) according to Le chatelain's principle for a slightly exothermic reaction, an increase in temperature favors the reverse reaction producing less hydrogen. As a result, concentration of hydrogen in the reformation decreases with an increasing temperature.
c) to calculate the maximum hydrogen yield , both reaction must be complete
C3H8 + 3H2O ⇒ 3CO + 7H2( REFORMING)
CO + H2O ⇒ CO2 + H2 ( SHIFTING)
C3H8 + 6H2O ⇒ 3CO2 + 10 H2 ( OVER ALL)
SO,
Maximum hydrogen yield
= 10mol h2/3 molco2 + 10molh2
= 0.77
⇒ 77%
Answer:
a) ≈ 30 mins
b) 8 vpm
Explanation:
<u>a) Determine how long after the first vehicle arrival will the queue dissipate</u>
The time after the arrival of the first vehicle for the queue to dissipate
= 29.9 mins ≈ 30 mins
<u>b) Determine the average service rate at the parking lot gate </u>
U = A / t
where : A = 240 vehicles , t = 30
U = 240 / 30 = 8 Vpm
attached below is a detailed solution of the given problems above
Answer:
The crash rate is 22 vehicles per 1 million vehicles
Explanation:
In this question, we are asked to determine the crash rate per million vehicles.
Crash rate is calculated using average crash frequency.
The crash rates are calculated based on the number of crashes per million vehicle miles travelled in a year.
Mathematically;
crash rate = (48 * 1,000,000)/ [(980 + 1560 + 1230 + 900 + 1435)* 365]
= 48,000,000/(6105*365)
= 21.54 approximately 22
Answer:
h=32.1 km
Explanation:
<em>solution:</em>
using newton law of gravitational attraction and newton second law:


r= distance between two masses
at sea level
a=g

.............................(1)
.........................(2)
by substituting (2) and (1)
acceleration due to gravity at a distance r from the centre of the earth in terms of g (sea level)
so the weight of the object at a distance r from the centre of the earth (W=ma)
W=mg(Re^2/r^2)..........(3)
h the height above the surface of the earth: r=Re+h
putting the value of r in eq (3)
W=mg(Re/Re+h)^2
W=0.99 mg
solving for height h:
h=Re(1/√0.99)-(1))
h=32.1 km