List and briefly describe two modern's materials needs
1 answer:
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Answer:
drag coefficient for the parachute is Cd = 1.84177
Explanation:
given data
diameter = 8.0 m
average vertical speed = 3 m/s
total weight of load = 200 N
to find out
drag coefficient for the parachute
solution
we will apply here drag coefficient formula that is express as here
drag coefficient Cd = ......................1
here w is total load and A is area and v is speed
and here ρ = 1.22 kg/cu
put here value we get
Cd =
Cd = 1.84177
drag coefficient for the parachute is Cd = 1.84177
Answer:
0.05%
Explanation:
From the question, we have;
The yield strength of the mild steel, = 43.5 ksi
Young's modulus of elasticity, ∈ = 29,000 ksi
The total strain, = 0.2% = 0.002
The inelatic strain is given as follows;
=
-
/∈
Therefore, we have;
= 0.002 - 43.5/(29,000) = 0.0005
Therefore, the inelastic strain, = 0.0005 = 0.05%
Taking the inelastic strain as the residual strain, we have;
The residual strain = 0.05%