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ddd [48]
4 years ago
15

List and briefly describe two modern's materials needs

Engineering
1 answer:
Angelina_Jolie [31]4 years ago
4 0

Answer:

Modern and smart materials for making the products are improved by developing new materials and find new uses for the existing. As, modern industrialization society is increased demand and quality of the product.

Two modern's materials are:

Carbon Fiber: As, carbon fiber is a strong material and it is light in weight. Designers used it because it is five times strong as steel and two times as stiff. Carbon fiber is basically made out of very thin strands of carbon.

Fiber Optics: It is a new technology as, it is used as transparent solid to transmitted light signals.

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Boats float because the gravity is acting down on it and the buoyant force is acting up on the ship.
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3 years ago
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11) If the evaporating pressure was 76 psig for r-22and the compressor inlet temperature was 65f, what would be the total superh
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7 0
3 years ago
What is the step in which you are testing your hypothesis ​
jonny [76]

Answer:

Step 1: State your null and alternate hypothesis. ...

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8 0
2 years ago
A 8.0-m-diameter parachute of a new design is to be used to transport a load from flight altitude to the ground with an average
S_A_V [24]

Answer:

drag coefficient for the parachute is Cd = 1.84177

Explanation:

given data

diameter = 8.0 m

average vertical speed = 3 m/s

total weight of load = 200 N

to find out

drag coefficient for the parachute

solution

we will apply here drag coefficient formula that is express as here  

drag coefficient Cd = \frac{2w}{\rho v^2A}    ......................1

here w is total load and A is area and v is speed

and here ρ = 1.22 kg/cu

put here value we get  

Cd = \frac{2*4*200}{1.229*5^2*\pi * 3^2}  

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drag coefficient for the parachute is Cd = 1.84177

3 0
3 years ago
Consider a mild steel specimen with yield strength of 43.5 ksi and Young's modulus of 29,000 ksi. It is stretched up to a point
mezya [45]

Answer:

0.05%

Explanation:

From the question, we have;

The yield strength of the mild steel, \sigma _c = 43.5 ksi

Young's modulus of elasticity, ∈ = 29,000 ksi

The total strain, \epsilon _c = 0.2% = 0.002

The inelatic strain \epsilon_c^{in} is given as follows;

\epsilon_c^{in} = \epsilon _c - \sigma _c/∈

Therefore, we have;

\epsilon_c^{in} = 0.002 - 43.5/(29,000) = 0.0005

Therefore, the inelastic strain, \epsilon_c^{in} = 0.0005 = 0.05%

Taking the inelastic strain as the residual strain, we have;

The residual strain = 0.05%

7 0
3 years ago
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