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Helga [31]
2 years ago
8

Will the fire started by burning magnesium and methane let out by a fire extinguisher?! THIS IS EMERGENCY HERE!

Chemistry
2 answers:
xxMikexx [17]2 years ago
7 0

Answer:

uh yes?

Explanation:

gogolik [260]2 years ago
7 0

Answer:

i think so just try it

Explanation:

good luck

You might be interested in
Identify any incorrect formulas. Explain your answer.
stepladder [879]
A is incorrect because Mg has a 2+ charge, while SO4 has a 2- charge, if there is 2 Mg and 3 SO4 then the formula will not add to 0 meaning neutral
5 0
2 years ago
A reaction produces 0.861 moles of H2O . How many molecules of H2O are produced?
ioda

Answer:

5.19 x 10²³ molecules of H₂O

Explanation:

1 mole => 6.023 x 10²³ molecules of H₂O

0.861 mole => 0.861mole x 6.023 x 10²³ molecules of H₂O

= 5.19 x 10²³ molecules of H₂O

4 0
3 years ago
Answer true or false and please explain why.
AlekseyPX

true because of this When water vapor in the atmosphere loses heat and cools down, condensation happens. As the water vapor cools down and condenses, it attaches to small particles of dust floating in the atmosphere, forming tiny liquid water droplets.

8 0
2 years ago
50.0 g of copper was dropped into 250.0mL of H2O at 25.0°C in a coffee cup calorimeter. The copper and H2O reached thermal equil
siniylev [52]

Answer:

Initial temperature of copper = 163.3 °C

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = final temperature - initial temperature

Given data:

Mass of copper = 50 g

Initial temperature of copper = ?

Final temperature = 27.5°C

Initial temperature of water = 25.0°C

Specific heat capacity of copper = 0.385 j/g.°C

Specific heat capacity of water = 4.184 J/g°C

Volume of water = 250.0 mL or 250.0 g

Solution:

Formula:

- Qm  =  +Qw

Now we will put the values in formula.

-50 g × 0.385 j/g.°C × [ 27.5°C -x] = 250 g × 4.184 J/g°C × [ 27.5°C - 25.0°C]

-50 g × 0.385 j/g.°C × [ 27.5°C -x] = 250 g × 4.184 J/g°C × 2.5°C

-19.25 j/°C × [ 27.5°C -x] = 2615 j

27.5°C -x =   2615 j / -19.25 j/°C

27.5°C -x = -135.8°C

x =  27.5°C + 135.8°C

x = 163.3 °C

7 0
3 years ago
Halp!
Nadya [2.5K]

Answer:

One with mass 0.52kg will have higher acceleration.

Explanation:

We know that

F = m x a

As we can see, for a constant value of F , for a body having more mass will have less acceleration and a body having less mass will have more acceleration ( Inversely proportional when force applied is constant).

Therefore lesser mass body will have more acceleration.

Hence, <em>0.52 kg body will have more acceleration. </em>

Verification :

F = ma

For 0.52kg:

a= F / m = 26 / 0.52 = 50 m/s²

For 0.78kg:

a= F/m = 26 / 0.78 = 33.3 m/s²

5 0
3 years ago
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