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fenix001 [56]
3 years ago
14

how would it affect your results if you use a wet Erlenmeyer flask instead of a dry one when transferring your acid solution fro

m a volumetric pipette? pls someone answer pls​
Chemistry
2 answers:
zloy xaker [14]3 years ago
8 0
With a wet Erlenmeyer flask, the result will not be accurate. It might be contaminated by any type of liquid such as basic or acidic. Therefore, an error will occur since it is not 100% acid.- hope this helped
solniwko [45]3 years ago
8 0

Explanation:

Your results would be effected because there is a possibility that the water and chemical substance added into the flask will combine, possibly creating a reaction, either making the solution stronger or weaker, or possibly just messing up your experiment in one go.

For example:

If I paint a picture, and I have a cup that I use in order to put paint in, but the cup is wet and I put my paint in it, my paint will become more liquefied due to the fact water has been added to it, messing the paint up.

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3 years ago
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1 What direction do<br> molecules move in?
notsponge [240]

Answer:

The majority of the molecules move from higher to lower concentration, although there will be some that move from low to high. The overall (or net) movement is thus from high to low concentration.

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3 0
3 years ago
a cube of iron (cp = 0.450 j/g•°c) with a mass of 55.8 g is heated from 25.0°c to 49.0°c. how much heat is required for this pro
krek1111 [17]
Q = ?

Cp = 0.450 j/g°C

Δt =  49.0ºC - 25ºC => 24ºC

m = 55.8 g

Q = m x Cp x Δt

Q = 55.8 x 0.450 x 24

Q = 602.64 J

hope this helps! 
7 0
3 years ago
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What type(s) of intermolecular forces exist between two molecules of hexane? (BLB Ch. 11)
kati45 [8]

Answer:

induced dipole-dipole forces or London Dispersion forces / van der Waals forces.

Explanation:

Hexane is non-polar in nature. This is due to :

The bond in the molecule is C-H, which is non-polar in nature because the carbon and the hydrogen having very similar electronegativity values.

Hexane is also symmetric.

The intermolecular force acting in the molecule of the hexane are induced the dipole-dipole forces or London Dispersion forces / van der Waals forces.

7 0
3 years ago
Heat is transferred directly from a heat reservoir at 200 C to another heat reservoir at 5C. If the amount of heat transferred i
Daniel [21]

Answer:

ΔS=0.148  KJ/K

Explanation:

Given that

Q = 100 KJ

T₁=200°C

T₁=200+273 = 437 K

T₂=5°C

T₂=5 + 273 = 278 K

Reservoir 1 is rejecting heat that is why it taken as negative while the reservoir 2 is gaining the heat that is why it is taken as positive.

So the total change in entropy given as

ΔS=  - Q/T₁ + Q/T₂

ΔS=  - 100/473 + 100/278  KJ/K

ΔS=0.148  KJ/K

4 0
3 years ago
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