What is the SI unit for distance?

Dr. Potter provides vaccinations against polio and measles.

vaieri [72.5K]

Answer:

hi zzayn i will solve this later

Explanation:

Let's establish that x= number of polio vaccinations and y=number of measles vaccinations.

Since Dr. P gave a total of 60 VACCINATIONS, we know that x+y=60. (This is equation #1)

We also know that Dr. P gave a total of 184 DOSES of the vaccinations and that the polio vaccine has 4 doses, while the measles vaccine has 2 doses. This means that our second equation is 4x+2y=184. (This is equation #2)

You can get either variable (x or y) by itself from equation #1. I always choose x.

x+y=60

-y. -y

x=60-y

Now we can plug our x value into equation #2.

4x+2y=184

4(60-y)+2y=184

240-4y+2y=184

240-2y=184

-240 -240

-2y=-56

/-2 /-2

y=28 measles vaccines

So we know that Dr. P administered 28 measles vaccines. We need to plug our y value back into equation #1 (or, to make it easier, our switched around equation) to find the number of polio vaccines.

x=60-y

x=60-28

x=32 polio vaccines

3 0

3 years ago

Read 2 more answers

An astronaunt takes am object to the moon where there is less gravity. Explain how the mass amd weight of an object on the moon

telo118 [61]

Even tho the object is big it will still Float around like a balloon cause of the gravity in space that's why they hook the rocket-ship into the ground of space

6 0

3 years ago

A 300 g wooden block on a smooth, level surface is firmly attached to a very light horizontal spring with a spring constant of 2

Tom [10]

the solution for the oscillatory movement allows to find the result for the amplitude of the initial displacement is:

The range of motion is: A = 4.44 cm

<h3>Oscillatory movement.</h3>

The oscillatory periodic motion of a system occurs when there is a recovered force, in the special case that this force is proportional to the displacement is called simple harmonic motion, which is described by the expression.

x = A cos (wt + Ф)

w² = k/m

where x is the displacement, A the amplitude, w the angular velocity, t the time, k the spring constant, m the mass, and Ф a phase constant determined by the initial conditions.

Let's find the angular velocity/

w= $\sqrt{ \frac{200}{0.300} }$

w = 25.8 rad/s

Let's look for the constant Ф, as the system is released from rest its initial velocity is zero, for zero time. The definition of speed is:

v= $\frac{dx}{dt}$

v= - A w sin (wt +Ф)

0 = -A w sin Ф

Ф= 0

They indicate that at a given instant of the time the velocity is v= 50.0 cm/s and it is in a position x= 4.00 cm, let us write the equations for this time

Position.

4.00 = A cos 25.8t

Speed.

50.0 = - At 25.8 sin 25.8t

To solve the system, ;et's square and add.

Cos² 25.8t = $\frac{16}{A^2}$

sin² 25.8t = $\frac{3.756}{A^2 }$

1 = $\frac{1}{A^2} \ (16 + 3.756)$

A = $\sqrt{19.756}$

A= 4.44 cm

In conclusion using the solution for the oscillatory movement we can find the result for the amplitude of the initial displacement is:

The range of motion is: A = 444 cm

Learn more about oscillatory motion here: brainly.com/question/14311816

4 0

2 years ago

A football is thrown due north across a 40 meter river and it takes 2 seconds to cover that distance.

Alexxx [7]

Answer:

I. Speed = 20m/s

II. Velocity = 20m/s due North.

Explanation:

<u>Given the following data;</u>

Distance = 40m

Time = 2secs

To find the speed;

Mathematically, speed is given by the formula;

$Speed = \frac{distance}{time}$

Substituting into the equation, we have;

$Speed = \frac{40}{2}$

<em>Speed = 20m/s.</em>

In physics, we use the same formula for calculating speed and velocity. The only difference is that speed is a scalar quantity and as such has magnitude but no direction while velocity is a vector quantity and as such it has both magnitude and direction.

$Velocity = \frac{distance}{time}$

<em>Therefore, the velocity is 20m/s due North</em>.

6 0

3 years ago

A student walks 350 m [S], then 400 m [E20°N], and finally 550 m [N10°W]. Using the component method, find the resultant (total)

levacccp [35]

In component form, the displacement vectors become

• 350 m [S] ==> (0, -350) m

• 400 m [E 20° N] ==> (400 cos(20°), 400 sin(20°)) m

(which I interpret to mean 20° north of east]

• 550 m [N 10° W] ==> (550 cos(100°), 550 sin(100°)) m

Then the student's total displacement is the sum of these:

(0 + 400 cos(20°) + 550 cos(100°), -350 + 400 sin(20°) + 550 sin(100°)) m

≈ (280.371, 328.452) m

which leaves the student a distance of about 431.8 m from their starting point in a direction of around arctan(328.452/280.371) ≈ 50° from the horizontal, i.e. approximately 431.8 m [E 50° N].

5 0

2 years ago